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3 years ago

In the celebrated equation e = mc2, the c2 is the _________.

1 answer:

5 0

Hello!

In the celebrated equation e = mc2, the c2 is the proportionality constant of energy and mass.

This famous equation was proposed by Albert Einstein in 1905, and implies that when there is a certain mass, there is a certain amount of Energy associated with it even is the mass is in a steady state. The proportionality constant c² is the speed of light squared.

Have a nice day!

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Is this an example of decomposition 2CH4 + 402 → 2C02 + 4H2O

Molodets [167]

Answer:

Identify each equation as a composition reaction, a decomposition reaction, or neither.

Fe2O3 + 3 SO3 → Fe2(SO4)3

NaCl + AgNO3 → AgCl + NaNO3

(NH4)2Cr2O7 → Cr2O3 + 4 H2O + N2

Solution

In this equation, two substances combine to make a single substance. This is a composition reaction.

Two different substances react to make two new substances. This does not fit the definition of either a composition reaction or a decomposition reaction, so it is neither. In fact, you may recognize this as a double-replacement reaction.

A single substance reacts to make multiple substances. This is a decomposition reaction.

Test Yourself

Identify the equation as a composition reaction, a decomposition reaction, or neither.

C3H8 → C3H4 + 2 H2

Explanation:

I hope I help :)))

5 0

3 years ago

How do I find the moles of OH- which reacted (mol) in the titration. Table Attached

BaLLatris [955]

Answer:

It is equal to the number of moles of acid that reacted. When Oxalic acid is your limiting reactant it is the # of moles of oxalic acid used. When NaOH is your limiting reactant it is equal to the number of moles of NaOH used.

4 0

2 years ago

What volume of 0.152 M KMnO4 solution would completely react with 20.0 mL of 0.381 M FeSO4 solution according to the following n

ANEK [815]

Answer: The volume of permanganate ion (potassium permanganate) is 10.0 mL

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of ferrous sulfate solution = 0.381 M

Volume of solution = 20.0 mL = 0.020 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.381M=\frac{\text{Moles of ferrous sulfate}}{0.020L}\\\\\text{Moles of ferrous sulfate}=(0.381mol/L\times 0.020L)=0.00762mol$

For the given chemical equation:

$5Fe^{2+}+8H^++MnO_4^-\rightarrow 5Fe^{3+}+Mn^{2+}+4H_2O$

By Stoichiometry of the reaction:

5 moles of iron (II) ions (ferrous sulfate) reacts with 1 mole of permanganate ion (potassium permanganate)

So, 0.00762 moles of iron (II) ions (ferrous sulfate) will react with = $\frac{1}{5}\times 0.00762=0.00152mol$ of permanganate ion (potassium permanganate)

Now, calculating the volume of permanganate ion (potassium permanganate) by using equation 1, we get:

Molarity of permanganate ion (potassium permanganate) = 0.152 M

Moles of permanganate ion (potassium permanganate) = 0.00152 mol

Putting values in equation 1, we get:

$0.152mol/L=\frac{0.00152mol}{\text{Volume of permanganate ion (potassium permanganate)}}\\\\\text{Volume of permanganate ion (potassium permanganate)}=\frac{0.00152mol}{0.152mol/L}=0.01L=10.0mL$

Hence, the volume of permanganate ion (potassium permanganate) is 10.0 mL

3 0

3 years ago

A substance is tested and has a pH of 1.2. How would you classify it?

djyliett [7]

Answer:

A weak acid

Explanation:

Im not sure if its right. But lets see someone else do it.

6 0

2 years ago

Read 2 more answers

Calculate the volume in L of 11.6 moles of Neon at 120 K when it has a pressure of 25.9 atm

beks73 [17]

Answer:

The volume of the gas is approximately 4.41 liters

Explanation:

The details of the data of the Neon gas are;

The number of moles of Neon gas present, n = 11.6 moles

The temperature of the sample of Neon gas, T = 120 K

The pressure of the sample of the Neon gas, P = 25.6 atm

By the ideal gas equation, we have;

P·V = n·R·T

Where;

R = The universal gal constant = 0.08205 L·atm·mol⁻¹·K⁻¹

Therefore, we get;

V = n·R·T/P

Which gives;

V = 11.6 moles × 0.08205 L·atm·mol⁻¹·K⁻¹ × 120 K/(25.9 atm) ≈ 4.4097915 L

The volume of the gas, V ≈ 4.41 L.

7 0

3 years ago