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zvonat [6]
2 years ago
9

Why is oxygen diflouride a gas at room temperature?

Chemistry
1 answer:
atroni [7]2 years ago
3 0

Answer:

Oxygen is a simple molecular structure, where individual oxygen atoms are bonded to each other by strong covalent bonds. Hence, a low amount of energy is required to overcome these weak forces and oxygen has a low boiling point. Therefore, at room temperature, oxygen is a gas. Oxygen difluoride is a colorless gas, condensable to a pale yellow liquid, with a slightly irritating odor. It is the most stable of the compounds of fluorine and oxygen, which include O,F,, O,F, and 0,F2 but nevertheless it is a strong oxidizing and fluorinating agent. Oxygen Difluoride is a colorless gas or a yellowish-brown liquid with a foul odor. Just to finally link Joseph's answer to the question, oxygen difluoride will thus change from liquid to solid state when chilled from -220°c to -230°c. The boiling point of oxygen is -182.96 degrees Celsius (under 1 standard atmosphere). This means at temperatures below that point, oxygen is a solid or a liquid, and at temperatures above that point, oxygen is a gas. So at -183 degrees Celsius, oxygen is a liquid.

Explanation:

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Answer:

<em>b</em>

Explanation:

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4 0
3 years ago
Identify the blocks and groups of elements in the periodic table​
djyliett [7]

Explanation:

The periodic table is a table that arranges elements based on their atomic numbers into groups and periods.

The groups are the vertical arrangement of elements. All elements in a group share similar chemical properties because they have the same number of elements in their valence shell. The periodic table groups are:

               Group                             Other names

              1A or 1                               Alkali metals

              IIA or 2                              Alkaline earth metals

             IIIA or 3                            Boron family

             VIA or 6                             Chalcogens

            VIIA or 17                            Halogens

             O-18                                  Inert elements

             IIIB-IIB                              Transition elements

There are 18 vertical columns divided into 8 tall groups or main groups which are 1A to O. The short groups or subgroups are from numerals 1B to VIII.

The periodic table can be divided into four blocks based on the type of sublevels their valence electrons occupy.

  • Group IA and IIA constitute the s-block
  • Group IIIA to O constitute the p-block
  • The transition elements makes up the d-block
  • The lanthanides and actinides makes up the f-block

Learn more:

Periodic table brainly.com/question/2014634

#learnwithBrainly

3 0
3 years ago
What is agovado constant
kirza4 [7]
6.02214086 x 10^23 mol^-1
7 0
3 years ago
Five calcite, CaCO3 (MM 100.085 g/mol), samples of equal mass have a total mass of 12.2±0.1 g . What is the average mass and abs
Westkost [7]

Answer:

  • <em>The average mass of calcium in each sample is: </em><u>0.978 g</u>

<em />

  • <em>The absolute uncertainty is: </em><u>0.008 g</u>

Explanation:

The <em>absolute uncertainty </em>of the total samples indicated in the statement is ± 0.1 g.

When you multiply or divide quantities with uncertainties, you calculate the final uncertanty by adding the <em>relative uncertainties</em> together.

The relative uncertainty is the absolute uncertainty divided by the quantity:

  • Relative uncertainty = 0.1g / 12.2 g = 0.008

The average mass of calcium is calculated using proportions, along with the molar masses:

  • Molar mass of calcium: 40.078 g/ mol (from a periodic table)

  • Molar mass of calcite: 100.085 g/mol (given)

Proportion:

  • 40.078 g of calcium / 100.085 g of calcite = x / 12.2 g of calcite

  • x = 12.2 × 40.078 / 100.085 g = 4.89 g calcium

So the total mass of calcium in the five samples is 4.89 g, and the average mass in each sample is:

  • Average mass = total mass of five samples / number of samples

  • Average mass = 4.89 g / 5 = <u>0.978 g of calcium</u>

So, the first answer is that the average mass of calcium in each sample is 0.978 g ( keep 3 signficant figures, such as the quntitiy 12.2 shows, as  you have only used multiplication and division).

The absolute uncertainty of each sample is the relative uncertainty multiplied by the average mass of calcium of the five samples, rounded to one decimal:

  • Absolute uncertainty = 0.978 g × 0.008 ≈ 0.008 g

The answer to the secon question is that the absolute uncertaingy of calcium in each sample is 0.008 g.

7 0
3 years ago
Answer Fast Please!!!
den301095 [7]

Answer:

The Periodic Table is organized in order of atomic number.

Explanation:

Plz give me brainliest I worked hard on this... thank u in advance.

8 0
3 years ago
Read 2 more answers
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