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3 years ago

Why is oxygen diflouride a gas at room temperature?

Chemistry

1 answer:

atroni [7]3 years ago

3 0

Answer:

Oxygen is a simple molecular structure, where individual oxygen atoms are bonded to each other by strong covalent bonds. Hence, a low amount of energy is required to overcome these weak forces and oxygen has a low boiling point. Therefore, at room temperature, oxygen is a gas. Oxygen difluoride is a colorless gas, condensable to a pale yellow liquid, with a slightly irritating odor. It is the most stable of the compounds of fluorine and oxygen, which include O,F,, O,F, and 0,F2 but nevertheless it is a strong oxidizing and fluorinating agent. Oxygen Difluoride is a colorless gas or a yellowish-brown liquid with a foul odor. Just to finally link Joseph's answer to the question, oxygen difluoride will thus change from liquid to solid state when chilled from -220°c to -230°c. The boiling point of oxygen is -182.96 degrees Celsius (under 1 standard atmosphere). This means at temperatures below that point, oxygen is a solid or a liquid, and at temperatures above that point, oxygen is a gas. So at -183 degrees Celsius, oxygen is a liquid.

Explanation:

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Masja [62]

<u>Answer:</u> The moles of given hydrocarbon is 0.3 moles

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Given mass of ethane = 10.0 g

Molar mass of ethane = $[(2\times 12)+(6\times 1)]=30g/mol$

We need to divide the given value by the molar mass.

Putting values in above equation, we get:

$\text{Moles of ethane}=\frac{10.0g}{30g/mol}=0.3mol$

In case of multiplication and division, the number of significant digits is taken from the value which has least precise significant digits. Here, the least precise number of significant digits are 1.

Hence, the moles of given hydrocarbon is 0.3 moles

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nlexa [21]

Answer:

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son4ous [18]

Answer:

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Explanation:

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Answer:

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