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Alchen [17]
3 years ago
11

Describe how oxidation and reduction involve electrons, change oxidation numbers, and combine in oxidation-reduction reactions.

Chemistry
2 answers:
photoshop1234 [79]3 years ago
4 0
The process of oxidation is the loss of electrons or an increase in oxidation state by a molecule, atom or ion and reduction is the gain of electrons or a decrease in oxidation state. The oxidation number is the total number of electrons that an atom gains or loses in order to form a chemical bond with another atom. Redox reactions are electron transfer processes and include all chemical reactions in which atoms have their oxidation state changed. 
adell [148]3 years ago
4 0

Answer:Oxidation is the loss of electrons.

Reduction is the gain of electrons.

Oxidation increases the oxidation number.

Reduction decreases the oxidation number.

In an oxidation-reduction reaction, the electrons from the oxidized atom or ion are transferred to the atom or ion that is reduced.

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You have 4.5 x 10^24 particles of C3H8. How many grams are present?
Citrus2011 [14]

Answer:

33 g.

Explanation:

Hello there!

In this case, for these particle-mole-mass relationships problems, it is necessary for us to recall the following equivalence statement, based off the molar mass of the involved compound, C3H8, one mole of particles and the Avogadro's number:

1mol=44.11g=6.022x10^{23}molecules

In such a way, we can set up the following expression for the calculation of the mass in the given particles of propane:

4.5x10^{23}molecules*\frac{1mol}{6.022x10^{23}molecules} *\frac{44.11g}{1mol}\\\\33g

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3 0
3 years ago
At 1 atm, how much energy is required to heat 75.0 g H 2 O ( s ) at − 20.0 ∘ C to H 2 O ( g ) at 119.0 ∘ C?
Hitman42 [59]

Answer:

238,485 Joules

Explanation:

The amount of energy required is a summation of heat of fusion, capacity and vaporization.

Q = mLf + mC∆T + mLv = m(Lf + C∆T + Lv)

m (mass of water) = 75 g

Lf (specific latent heat of fusion of water) = 336 J/g

C (specific heat capacity of water) = 4.2 J/g°C

∆T = T2 - T1 = 119 - (-20) = 119+20 = 139°C

Lv (specific latent heat of vaporization of water) = 2,260 J/g

Q = 75(336 + 4.2×139 + 2260) = 75(336 + 583.8 + 2260) = 75(3179.8) = 238,485 J

3 0
3 years ago
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lys-0071 [83]

Explanation:

An enzyme inhibitor is a molecule that binds to an enzyme and decreases its activity. ... Since blocking an enzyme's activity can kill a pathogen or correct a metabolic imbalance, many drugs are enzyme inhibitors. They are also used in pesticides.

7 0
3 years ago
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Korolek [52]

Answer:the first one

Explanation:

7 0
2 years ago
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podryga [215]

Answer:metres

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