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3 years ago

Explain how chemical reactions apply to law of conservation of matter

1 answer:

3 0

The law of conservation of mass says that matter cannot be created or destroyed. This means that when a chemical reaction happens, you can never create new atoms or destroy the ones that are reacting, they simply rearrange themselves into new substances.

For purposes of looking at chemical equations, this means that the equation that describes the reaction has to be "balanced". In other words, there must be the same number and same kind of atoms on the reactant side of the equation as there are on the product side to ensure that no atoms are created or lost during the reaction.

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Milk is solid by the liter in many countries. What is the volume of exactly 1/2 gal of milk in liters?

Marizza181 [45]

Answer : The volume of milk in liters are, 1.8925 liters

Explanation :

The conversion used for volume from gallon to liter is:

(1 gallon = 3.785 liter)

As we are given the volume of milk in gallon is, $\frac{1}{2}$

Now we have to determine the volume of milk in liters.

As, 1 gallon of milk = 3.785 liter

So, $\frac{1}{2}$ gallon of milk = $\frac{\frac{1}{2}\text{ gallon}}{1\text{ gallon}}\times 3.785\text{ liter}=1.8925\text{ liter}$

Therefore, the volume of milk in liters are, 1.8925 liters

6 0

3 years ago

What is 800kj to calories

Mekhanik [1.2K]

Explanation:

1 calorie = 4.18J

800 kj = 800 × 1000

= 800000 j

800000 = 800000/ 4.18 calories

= 191387.5598 calories

= 1.9 × 10^5 calories

4 0

3 years ago

Which of the following set ups which converts centimeters to fit

Eva8 [605]

Answer:

The fourth one down

Explanation:

It is the only setup in which the units of "cm" and "in" cancel correctly and give the desired units of "ft."

The second one down has the correct units but the wrong conversion factor for converting centimetres to inches.

5 0

3 years ago

An ethylene glycol solution contains 21.4 g of ethylene glycol (C2H6O2) in 97.6 mL of water. (Assume a density of 1.00 g/mL for

8090 [49]

Answer: The freezing point and boiling point of the solution are $-6.6^0C$ and $101.8^0C$ respectively.

Explanation:

Depression in freezing point:

$T_f^0-T^f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_f$ = freezing point of solution = ?

$T^o_f$ = freezing point of water = $0^0C$

$k_f$ = freezing point constant of water = $1.86^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(0-T_f)^0C=1\times (1.86^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_f=-6.6^0C$

Therefore,the freezing point of the solution is $-6.6^0C$

Elevation in boiling point :

$T_b-T^b^0=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of water = $100^0C$

$k_b$ = boiling point constant of water = $0.52^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(T_b-100)^0C=1\times (0.52^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_b=101.8^0C$

Thus the boiling point of the solution is $101.8^0C$

4 0

3 years ago

Am I weird or is no one seeing my qn<br>free point by the way

Julli [10]

Answer:

maybe they don't want to answer it only if you give them a lot of points and brainliest they will answer it i think

Explanation:

5 0

1 year ago

Read 2 more answers