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Law Incorporation [45]
2 years ago
15

Explain why sodium chloride solution cannot be used as the electrolyte to produce

Chemistry
1 answer:
ira [324]2 years ago
6 0

Explanation:

Because the solution only contains Na+ and Cl− ions, and water, and not the metal Na(s) . You cannot evaporate the water from the solution and hope to obtain anything but NaCl(s) .

.

Na(s) has an electron configuration of 1s^2 2s^2 2p^6 3s^1 , but Na+(aq) has an electron configuration of 1s^2 2s^2 2p^6 . That means they are not the same element, and thus, there is no straightforward way of extracting Na(s) from a NaCl (aq) solution

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Reactant(s)<br> H<br> 0,<br> Product(s)<br> H,0<br> 3.4g<br> 10g
zalisa [80]

Answer:

H,0

3.4g

Explanation:

H,0

3.4g

8 0
3 years ago
What kind of energy is required for photosynthesis to occur​
Makovka662 [10]

Answer:

light energy to convert carbon dioxide and water into glucose and oxygen gas. Each molecule of glucose essentially “stores” up to 38 molecules of ATP which can be broken down and used during other cellular reactions.

Explanation:

6 0
3 years ago
Read 2 more answers
6.5 Moles of Al reacts with 7.2 Moles of H2O What is the limiting reactant and calculate the Theoretical Yield?
SVEN [57.7K]

Answer:

H₂O is the limiting reactant

Theoretical yield of 240 g Al₂O₃ and 14 g H₂

Explanation:

Find how many moles of one reactant is needed to completely react with the other.

6.5 mol Al × (3 mol H₂O / 2 mol Al) = 9.75 mol H₂O

We need 9.75 mol of H₂O to completely react with 6.5 mol of Al.  But we only have 7.2 mol of H₂O.  Therefore, H₂O is the limiting reactant.

Now find the theoretical yield:

7.2 mol H₂O × (1 mol Al₂O₃ / 3 mol H₂O) × (102 g Al₂O₃ / mol Al₂O₃) ≈ 240 g Al₂O₃

7.2 mol H₂O × (3 mol H₂ / 3 mol H₂O) × (2 g H₂ / mol H₂) ≈ 14 g H₂

Since the data was given to two significant figures, we must round our answer to two significant figures as well.

4 0
3 years ago
Why do group 1 cations form precipitates when mixed with hcl?
Xelga [282]
Both of you are overlooking a pretty big component of the question...the Group I cation isn't being dissociated into water. We're testing the solubility of the cation when mixed with HCl. And this IS a legitimate question, seeing as our lab manual is the one asking. 

<span>By the way, the answer you're looking for is "Because Group I cations have insoluble chlorides". </span>

<span>"In order...to distinguish cation Group I, one adds HCl to a sample. If a Group I cation is present in the sample, a precipitate will form." </span>
8 0
3 years ago
4. Which class of matter is the least evenly
lys-0071 [83]

Answer:

Pure iron sulfide is homogeneous (uniform in appearance and properties), shows constant composition (a consistent ratio of iron to sulfur throughout any sample of it, large or small), consists of molecules all of one type, is no longer separable into two separate substances without another chemical reaction, and is .

Explanation:

Mixtures in two or more phases are heterogeneous mixtures. ... The exception would be solutions that contain another phase of matter. For example, you can make a homogeneous solution of sugar and water, but if there are crystals in the solution, it becomes a heterogeneous mixture.

8 0
3 years ago
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