Answer: The isotopic abundance of Cl- 37 is 0.2424.
Explanation:
Mass of isotope - 35 = 34.96885 amu
% abundance of isotope -35= x% = ![\frac{x}{100}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B100%7D)
Mass of isotope - 37 = 36.9659 amu.
% abundance of isotope-37 = (100-x)% = ![\frac{100-x}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B100-x%7D%7B100%7D)
Formula used for average atomic mass of an element :
![\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})](https://tex.z-dn.net/?f=%5Ctext%7B%20Average%20atomic%20mass%20of%20an%20element%7D%3D%5Csum%28%5Ctext%7Batomic%20mass%20of%20an%20isotopes%7D%5Ctimes%20%7B%7B%5Ctext%20%7B%20fractional%20abundance%7D%7D%29)
![35.453=\sum[(34.96885 \times \frac{x}{100})+(36.9659 \times \frac{100-x}{100}]]](https://tex.z-dn.net/?f=35.453%3D%5Csum%5B%2834.96885%20%5Ctimes%20%5Cfrac%7Bx%7D%7B100%7D%29%2B%2836.9659%20%5Ctimes%20%5Cfrac%7B100-x%7D%7B100%7D%5D%5D)
![(100-75.76)=24.24\%=0.2424](https://tex.z-dn.net/?f=%28100-75.76%29%3D24.24%5C%25%3D0.2424)
Therefore, the isotopic abundance of Cl- 37 is 0.2424.
Answer:
the least malleable in its solid state A.phosphorus (P)
TWO more additional electron can fit into that....
Answer:
a) Equilibrium shifts in forward direction.
Explanation:
If pressure is increased, equilibrium shifts to the side with the fewer moles of gas.
There are 4 moles of gas in the reactants and 2 moles of gas in the products.
The equilibrium will shift in the forward direction towards the products.
Hope that helps.