Question

A weather balloon was initially at a pressure of 0.950 atm, and its volume was 35.0 L. The pressure decreased to 0.750 atm, without loss of gas or change in temperature. What was the change in the volume

Answer 1

Answer: The change in volume will be 9.30 L

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=0.950atm\\V_1=35.0L\\P_2=0.750atm\\V_2=?L$

Putting values in above equation, we get:

$0.950\times 35.0L=0.750\times V_2\\\\V_2=44.3L$

The change in volume will be (44.3-35.0)L = 9.30 L