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slavikrds [6]
3 years ago
14

ICl has a higher boiling point than Br2. What is the best explanation for this?

Chemistry
2 answers:
Burka [1]3 years ago
8 0

Answer:

b. ICl experiences dipole-dipole interactions

Explanation:

The molecule with the <em>stronger intermolecular forces</em> will have the higher boiling point.

In Br₂, the Br-Br bond has a <em>dipole moment of zero</em>, because the two atoms are identical.

In ICl, the I-Cl bond, has two different atoms. One must be more electronegative than the other, so there will be a <em>non-zero bond dipole</em>.

ICl will have the higher boiling point.

a is <em>wrong</em>. Br₂ is nonpolar, so it has no dipole-dipole interactions.

c is <em>wrong</em>. Br₂ cannot form hydrogen bonds, because there is no hydrogen.

d is <em>wrong</em>. ICl has dipole-dipole interactions.

77julia77 [94]3 years ago
6 0

Answer:

B. ICl experiences dipole-dipole interactions.

Explanation:

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P_{CO_2}=25mmHg

Explanation:

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In this case, according to the Dalton's law, which explains that the total pressure of a gaseous system equals the sum of the partial pressures of the gases composing, for the gaseous mixture composed by oxygen, nitrogen and carbon dioxide it would be possible to write:

P_{tot}=P_{N_2}+P_{O_2}+P_{CO_2}

Now, given the pressure of the system and those of oxygen and nitrogen, we calculate that of carbon dioxide as shown below:

P_{CO_2}=P_{tot}-P_{N_2}-P_{O_2}\\\\P_{CO_2}=250mmHg-50mmHg-175mmHg\\\\P_{CO_2}=25mmHg

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