All categories

3 years ago

What is an orbital????

Chemistry

1 answer:

kherson [118]3 years ago

3 0

Answer:

Orbital, in chemistry and physics, a mathematical expression, called a wave function, that describes properties characteristic of no more than two electrons in the vicinity of an atomic nucleus or of a system of nuclei as in a molecule. ... A 1s electron occupies the energy level nearest the nucleus.

Explanation:

You might be interested in

A piston containing 0.120moles of methane gas, CH4, has a volume of 2.12liters. If methane is added until the volume is increase

gizmo_the_mogwai [7]

Answer:

2.83 g

Explanation:

At constant temperature and pressure, Using Avogadro's law

$\frac {V_1}{n_1}=\frac {V_2}{n_2}$

Given ,

V₁ = 2.12 L

V₂ = 3.12 L

n₁ = 0.120 moles

n₂ = ?

Using above equation as:

$\frac{2.12}{0.120}=\frac{3.12}{n_2}$

$2.12n_2=0.12\cdot \:3.12$

$2.12n_2=0.3744$

$n_2=\frac{0.3744}{2.12}$

$n_2=0.17660$

n₂ = 0.17660 moles

Molar mass of methane gas = 16.05 g/mol

So, Mass = Moles*Molar mass = 0.17660 * 16.05 g = 2.83 g

<u>2.83 g are in the piston.</u>

8 0

3 years ago

A 0.495 g sample of iron containing salt required 20.22 mL of 0.0194 M permanganate solution to reach the endpointof a titration

kogti [31]

Answer:

% Fe in the sample = 22.0%

Explanation:

The redox reaction between iron and permanganate is:

$MnO_{4}^{-}+5Fe^{2+}+8H^{+}\rightarrow Mn^{2+}+5Fe^{3+}+4H2O$

Moles of permanganate required is:

$molarity*volume = 0.0194 mols/L*0.02022L = 0.000392\ moles$

Based on the reaction stoichiometry:

5 moles of iron requires 1 mole of permanganate solution

Therefore, 0.000392 mols of permanganate would need:

$=\frac{0.000392\ mols\ permanganate*5\ mols\ iron}{1\ mol\ permanganate} =0.00196\ mols$

Mol mass of iron (Fe) = 55.845 g/mol

Mass of iron present is:

$=moles*mol.mass = 0.00196mols*55.845g/mol=0.109 g$ $Percent\ iron = \frac{Mass(iron)}{Mass(sample)} *100\\\\Percent\ iron =\frac{0.109}{0.495} *100=22.0$

6 0

3 years ago

How many grams are in 2 moles of copper

alisha [4.7K]

Answer:

In 2 moles of copper, there are 319.2172 grams.

Explanation:

Quick conversion chart of moles Copper(II) Sulfate to grams 1 moles Copper(II) Sulfate to grams = 159.6086 grams 2 moles Copper(II) Sulfate to grams = 319.2172 grams

7 0

3 years ago

The following reactions are used in batteries:Reaction I is used in fuel cells, II in the automobile lead-acid battery, and III

elixir [45]

The highest ratio is -0.613kj/g which is for automobile lead-acid battery .

Given ,

Reaction-1 used in fuel cells

Reaction-2 used in automobile lead-acid battery

Reacttion-3 used in experimental high-temperature battery for powering electric vehicles .

1) Fuel cells :

2H2(g) + O2(g) ==> 2H20 (l) , E^0cell = 1.23V

We know ,

Free energy is the maximum work done .

delta G = Wmax

=> Wmax = delta G = -4.75*10^5j/mol e^- = -4.75*10^2 kj/ mol e^-

Molecular mass of 1 mole of H2 = 2 .016 g / mol e^-

Molecular mass of 2 mole of H2 = 4.032 g/mol e^-

Molecular mass of O2 = 32 g/mol e^-

Total mass of the reactants = (4.032+32)g/mol e^- = 36.032 g/mol e^-

Ratio of Wmax to the total mass of the reactants

=Wmax/ total mass of the reactants

=( -4.75*10^2 kj/mol e^-)/36.032 g/mol e^-

=-13.2kj/g

Therefore , the ratio of Wmax to total mass of the reactants is -13.2kj/g .

2) Automobile lead-acid battery :

Pb(s) + PbO2(s) + 2H2SO4(aq) ==> 2PbSO4 (s) + 2H2O (l) , E^0cell = 2.04V

We know ,

Wmax = delta G = -3.94*10^5j/mol e^- = -3.94*10^2kj/mol e^-

molecular mass of Pb = 207.2 g /mol e^-

molecular mass of Pbo2 = 239.2g/mol e^-

molecular mass of H2SO4 = 98.008g/mol e^-

molecular mass of 2 mole of H2SO4 = 196.016g/mol e^-

total mass of the reactants = (207.2+239.2+196.016)g/mol e^- = 642.416g/mol e^-

Ratio of Wmax to total mass of the reactants

= Wmax/total mass of reactants

=(-3.94*10^2kj/mol e^-)/642.416g/mol e^-

=-0.613kj/g

Hence ,the ratio of Wmax to the total mass of the reactants of automobile lead-acid battery is -0.613kj/g .

3) Experimental high temperature battery :

2Na(l) +FeCl2(s) ==> 2NaCl (s) + Fe(s) , E^0 cell = 2.35V

We know ,

Wmax = delta G = -4.53*10^5j/mol e^- = -4.53*10^2kj/mol e^-

molecular mass of Na = 22.99 g/mol e^-

molecular mass of 2 moles of Na = 45.98g/mol e^-

molecular mass of FeCl2 = 126.85 g/mol e^-

total mass of the reactants =( 45.98+ 126.85)g/mol e^- = 172.83 g/mol e^-

Ratio of Wmax to the total mass of the reactants

= Wmax / total mass of reactants

=(-4.53*10^2kj/mol e^-)/ 172.83g/mol e^-

=-2.62kj/g

Therefore , the ratio of Wmax to the total mass of the reactants in an experimental high temperature battery is -2.62kj/g .

Hence , the highest ratio is -0.613kj/g which is of lead -acid battery .

Learn more about fuel cell here :

brainly.com/question/13603874

#SPJ4

4 0

2 years ago

How do I do question number 2?

ale4655 [162]

Answer:

I cant help

Explanation:

4 0

3 years ago