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oksano4ka [1.4K]
3 years ago
14

Record the temperature shown on the thermometer to the nearest half of a degree.

Chemistry
2 answers:
Lina20 [59]3 years ago
5 0

Answer:

22.5

Explanation:

VikaD [51]3 years ago
3 0

Answer:

22.5

Explanation:

I did the assignment

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Which answer choice correctly describes the gas law and physical changes represented by the image?
skelet666 [1.2K]

Answer:

<h2>A. The image shows Boyle's Law because volume decreases as pressure increases.</h2>

Explanation:

According to Boyle's Law, at constant temperature, pressure and volume have inverse relation that is as pressure would increase, volume would decrease.

According to Charles Law, at constant pressure, the volume is directly proportional to temperature.

According to the given graph and diagram, the temperature is constant and volume and pressure have inverse relation.

Thus, option A is correct.

5 0
4 years ago
Read 2 more answers
In an ionic bond, Select one:
Elena-2011 [213]

Answer:

A

Explanation:

B - Can't be - Ionic bonds are formed by oppositely charged ions

C - Can't be - This is a covalent bond

D - Can't be - This is an induced dipole or a van Der waals attraction

E - This is a permanent dipole dipole attraction

8 0
3 years ago
Assume that the NO, concentration in a house with a gas stove is 150 pg/m°. Calculate the equivalent concentration in ppm at STP
jok3333 [9.3K]

Explanation:

It is known that for NO_{2}, ppm present in 1 mg/m^{3} are as follows.

                      1 \frac{mg}{m^{3}} = 0.494 ppm

So, 150 pg/m^{3} = \frac{150}{1000} mg/m^{3}

                       = 0.15 mg/m^{3}

Therefore, calculate the equivalent concentration in ppm as follows.

             0.15 \times 0.494 ppm

              = 0.074 ppm

Thus, we can conclude that the equivalent concentration in ppm at STP is 0.074 ppm.  

4 0
3 years ago
The f-n-f bond angle in the nf3 molecule is slightly less than ________.
ale4655 [162]

Answer:

ysjsjskdmdddlsdldlehfjcmdkdudheb

Explanation:

jekeidndndmdjrrkddodn

7 0
2 years ago
For a first-order reaction, A → B, the rate coefficient was found to be 3.4 × 10-4 s-1 at 23 °C. After 5.0 h, the concentration
Illusion [34]

Answer:

the original concentration of A = 0.0817092  M

Explanation:

A reaction is considered to be of first order it it strictly obeys the graphical equation method.

k_1 = \dfrac{2.303}{t}log \dfrac{a}{a-x}

where;

k = the specific rate coefficient  = 3.4 × 10⁻⁴ s⁻¹

t = time   = 5.0 h = 5.0 × 3600 = 18000 seconds

a = initial concentration = ???

a - x = remaining concentration of initial concentration at time t = 0.00018 mol L⁻¹

3.4 \times 10^{-4}= \dfrac{2.303}{18000}log \dfrac{a}{0.00018}

3.4 \times 10^{-4}= 1.27944 \times 10^{-4} \times log \dfrac{a}{0.00018}

\dfrac{3.4 \times 10^{-4}}{1.27944 \times 10^{-4}}=   log \dfrac{a}{0.00018}

2.657=   log \dfrac{a}{0.00018}

10^{2.657}= \dfrac{a}{0.00018}

453.94 = \dfrac{a}{0.00018}

a =453.94 \times 0.00018

a = 0.0817092  M

Thus , the original concentration of A = 0.0817092  M

8 0
3 years ago
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