Answer: his score 131 points
Step-by-step explanation:
Assuming the scores in the standardized test are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = standardized test scores.
µ = mean score
σ = standard deviation
From the information given,
µ = 110 points
σ = 10 points
Looking at the normal distribution table, the z score that corresponds to the 98 percentile is 2.06
2.06 = (x - 110)/10
Cross multiplying, it becomes
2.06 × 10 = x - 110
2.06 = x - 110
x = 20.6 + 110
x = 130.6
Approximately, x = 131
