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masha68 [24]
3 years ago
6

A standardized test has a mean of 110 points and a standard deviation of 10 points. John scored at the 98th percentile on the te

st. Find his score to the nearest whole number.
Mathematics
1 answer:
Mariana [72]3 years ago
4 0

Answer: his score 131 points

Step-by-step explanation:

Assuming the scores in the standardized test are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = standardized test scores.

µ = mean score

σ = standard deviation

From the information given,

µ = 110 points

σ = 10 points

Looking at the normal distribution table, the z score that corresponds to the 98 percentile is 2.06

2.06 = (x - 110)/10

Cross multiplying, it becomes

2.06 × 10 = x - 110

2.06 = x - 110

x = 20.6 + 110

x = 130.6

Approximately, x = 131

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10 < 0.25 ( x + 1 ) < 11
AURORKA [14]
10 <0.25 (x + 1) <11
 
We must solve two inequalities in this case.
 Inequality 1:
 
10 <0.25 (x + 1)
 10 / 0.25 <x + 1
 40 <x + 1
 40-1 <x
 39 <x
 Inequality 2:
 
0.25 (x + 1) <11
 (x + 1) <11 / 0.25
 (x + 1) <44
 x <44-1
 x <43
 The final result is:
 39 <x <43
 Answer:
 
39 <x <43
6 0
3 years ago
One angle of a triangle measures <img src="https://tex.z-dn.net/?f=10degrees" id="TexFormula1" title="10degrees" alt="10degrees"
iVinArrow [24]

Answer:

One\ angle: 35^o\\Second\ angle: 25^o\\Third\ angle: 120^o

Step-by-step explanation:

Let

x ----> the measure of one angle of the triangle

y ---> the measure of the second angle

z ----> the measure of the third angle

we know that

The sum of the measure of the interior angles in any triangle must be equal to 180 degrees

x+y+z=180^o -----> equation A

One angle of a triangle measures  10 degrees more than the second

x=y+10 ----> equation B

The measure of the third angle is twice the sum of the first two angles

z=2(x+y) ---> equation C

substitute equation B in equation C

z=2(y+10+y)

z=4y+20 ----> equation D

substitute equation D and equation B in equation A

(y+10)+y+(4y+20)=180^o

solve for y

6y=180-30\\6y=150\\y=25^o

Find the value of x

x=25+10=35^o

Find the value of z

z=4(25)+20=120^o

therefore

One\ angle: 35^o\\Second\ angle: 25^o\\Third\ angle: 120^o

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