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3 years ago

6

A vertical line has points C, E, F from top to bottom. 2 lines extend from point E. One line extends to point A and another exte

nds to point B. Angle A E C is 90 degrees.
Given that Ray E B bisects ∠CEA, which statements must be true? Select three options.

m∠CEA = 90°
m∠CEF = m∠CEA + m∠BEF
m∠CEB = 2(m∠CEA)
∠CEF is a straight angle.
∠AEF is a right angle.

2 answers:

STatiana [176]3 years ago

7 0

Answer:

A, D, E

Step-by-step explanation:

Alex Ar [27]3 years ago

4 0

It would be something I’m just not sure

You might be interested in

Help is much needed :)

dangina [55]

Answer:

13

Step-by-step explanation:

EG=25

EF=12

FG=25-12=13

3 0

3 years ago

You intend to estimate a population proportion with a confidence interval. The data suggests that the normal distribution is a r

SIZIF [17.4K]

Answer:

The critical value that corresponds to a confidence level of 99% is, 2.58.

Step-by-step explanation:

Consider a random variable <em>X</em> that follows a Binomial distribution with parameters, sample size <em>n </em>and probability of success <em>p</em>.

It is provided that the distribution of proportion of random variable <em>X, </em> $\hat p$ , can be approximated by the Normal distribution.

The mean of the distribution of proportion is, $\mu_{\hat p}=\hat p$

The standard deviation of the distribution of proportion is, $\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$ .

Then the confidence interval for the population proportion <em>p</em> is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }$

The confidence level is 99%.

The significance level is:

$\alpha =1-\frac{Confidence\ level}{100}=1-\frac{99}{100}=1-0.99=0.01$

Compute the critical value as follows:

$z_{\alpha /2}=z_{0.01/2}=z_{0.005}$

That is:

$P(Z>z)=0.005\\P(Z$

Use the <em>z</em>-table for the <em>z-</em>value.

For <em>z</em> = 2.58 the P (Z < z) = 0.995.

And for <em>z</em> = -2.58 the P (Z > z) = 0.005.

Thus, the critical value is, 2.58.

7 0

4 years ago

Given a map scale of 1 inch = 10 km, what is the distance between two mountains that measure 1.25 in. apart on the map?

balu736 [363]

The easiest way to solve this problem is to just move the decimal point to the right one place.

1.25 → 12.5

Your answer should be 12.5

4 0

3 years ago

Read 2 more answers

Tom and Becky can paint Jim's fence together in 12 hours. If all people paint at the same rate, how many hours would it take to

Delvig [45]

Answer: 8 hours

Step-by-step explanation:

Let x be the time taken by each person to paint the fence.

Given: Tom and Becky can paint Jim's fence together in 12 hours.

Since all people paint at the same rate, then we have the following equation ;-

$\dfrac{1}{x}+\dfrac{1}{x}=\dfrac{1}{12}\\\\\Rightarrow\ \dfrac{2}{x}=\dfrac{1}{12}\\\\\Rightarrow\ x=24$

Thus, the time taken by each person to paint the fence alone = 24 hours

Now, the time taken by all three paint together:-

$\dfrac{1}{t}=\dfrac{1}{24}+\dfrac{1}{24}+\dfrac{1}{24}\\\\\Rightarrow\ \dfrac{1}{t}=\dfrac{3}{24}\\\\\Rightarrow\ t=\dfrac{24}{3}=8\text{ hours}$

Hence, it would take 8 hours if all three paint together.

3 0

3 years ago

HELPPPP!!!!!!!! 100 points!!!! I need help on 37-39 thanks!

____ [38]

Answer:

Part 37)

a) Point-slope form $y-5=(1)(x-3)$

b) Slope intercept form $y=x+2$

c) Standard form $x-y=-2$

Part 38)

a) Point-slope form $y-2=0.25(x+4)$

b) Slope intercept form $y=0.25x+3$

c) Standard form $x-4y=-12$

Part 39)

a) Point-slope form $y-3=2(x-1)$

b) Slope intercept form $y=2x+1$

c) Standard form $2x-y=-1$

Step-by-step explanation:

Part 37) Line passing through point (3,5) and slope of 1

Part a) Equation of the line in point slope form

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute the given values

$y-5=(1)(x-3)$

$y-5=(x-3)$ -----> equation of the line in point slope form

Part b) Equation of the line into slope intercept form

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

Substitute the given values in the equation and solve for b

$5=(1)(3)+b$

$5=3+b$

$b=5-3$

$b=2$

substitute

$y=x+2$ -----> equation of the line in slope intercept form

Part c) Equation of the line in standard form

The equation of the line in standard form is equal to

$Ax+By=C$

where

A is a positive integer

B and C are integers

we have

$y=x+2$

Convert to standard form

Subtract y both sides

$y-y=x+2-y$

$0=x+2-y$

Subtract 2 both sides

$-2=x+2-y-2$

$-2=x-y$

Rewrite

$x-y=-2$ ----> equation in standard form

Part 38) Line passing through points (-4,2) and (0,3)

Part a) Equation of the line in point slope form

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

Find the slope m

$m=(3-2)/(0+4)=1/4=0.25$

with the slope m=0.25 and point (-4,2)

substitute the given values

$y-2=0.25(x+4)$ -----> equation of the line in point slope form

Part b) Equation of the line into slope intercept form

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$m=0.25$

$b=3$ -----> the y-intercept is the point (0,3)

Substitute the given values in the equation

$y=0.25x+3$ -----> equation of the line in slope intercept form

Part c) Equation of the line in standard form

The equation of the line in standard form is equal to

$Ax+By=C$

where

A is a positive integer

B and C are integers

we have

$y=0.25x+3$

Convert to standard form

Multiply by 4 both sides to remove the decimal number

$4y=x+12$

Subtract 4y both sides

$4y-4y=x+12-4y$

$0=x+12-4y$

Subtract 12 both sides

$-12=x+12-4y-12$

$-12=x-4y$

Rewrite

$x-4y=-12$ ----> equation in standard form

Part 39) Line passing through points (1,3) and (2,5)

Part a) Equation of the line in point slope form

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

Find the slope m

$m=(5-3)/(2-1)=2/1=2$

with the slope m=2 and point (1,3)

substitute the given values

$y-3=2(x-1)$ -----> equation of the line in point slope form

Part b) Equation of the line into slope intercept form

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

with the slope m=2 and point (1,3)

Substitute the given values and solve for b

$3=(2)(1)+b$

$3=2+b$

$b=3-2=1$

substitute

$y=2x+1$ -----> equation of the line in slope intercept form

Part c) Equation of the line in standard form

The equation of the line in standard form is equal to

$Ax+By=C$

where

A is a positive integer

B and C are integers

we have

$y=2x+1$

Convert to standard form

Subtract y both sides

$y-y=2x+1-y$

$0=2x+1-y$

Subtract 1 both sides

$-1=2x+1-y-1$

$-1=2x-y$

Rewrite

$2x-y=-1$ ----> equation in standard form

8 0

4 years ago