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CaHeK987 [17]
2 years ago
12

The density of a gas sample in a balloon is 1.50 g/l at 75°c. what is the density of this gas when the temperature is changed t

o 25°c at constant pressure?
Physics
1 answer:
maksim [4K]2 years ago
8 0

At 25°C, a gas sample's density in the balloon is 4.500 g/L.

When density decreases, temperature increases. When more temperature increases, density reduces. When the temperature decrease, density increases.

When a substance is heated, the molecules move faster and slightly farther apart, taking up more space and causing the density to drop. When something is cooled, the molecules slow down and get a little closer together, taking up less space and becoming denser.

The density of a gas sample in a balloon = 1.50 g/L

Temperature = 75°C

Temperature increased = 25°C

The density of a gas sample in the balloon at 25°C = (1.50 × 75)/ 25

                                                                                      = 4.500 g/L

Therefore, the density of a gas is 4.500 g/L.

Learn more about density here:

brainly.com/question/6838128

#SPJ4

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Answer:

c) depends only on the type of fluid

Explanation:

The pressure of a fluid at a specific depth is given by:

where

is the density of the fluid

g is the gravitational acceleration

h is the depth

We see that for a given depth h, the pressure of the fluid depends only on its density, so only on the type of fluid. Therefore, the correct choice is

a) depends only on the type of fluid

The other choices are wrong because:

b) the pressure is exerted in every direction

c) the pressure does not depend on the total volume of the fluid, but only on the depth h

4 0
3 years ago
1) Little Timmy wants to measure how tall his house is. He doesn’t have a tape measure but does have a stopwatch. He recruits Bi
kifflom [539]

1) 13.7 m

The motion of the rock is a free fall, with constant acceleration g=9.8 m/s^2 towards the ground, so the total distance it covers is given by the SUVAT equation:

S=\frac{1}{2}gt^2

where S is the height of the house, and t is the time the rock takes to reach the ground. Substituting t=1.67 s, we find:

S=\frac{1}{2}(9.8 m/s^2)(1.67 s)^2=13.7 m

2) 105.5 m

The motion of the stuffed chicken is a projectile motion, with a uniform horizontal motion (with constant velocity of v=36.0 m/s) and a vertical accelerated motion (with constant acceleration of g=9.8 m/s^2).

First of all, we can find the total time of the ball by considering the vertical motion only. We know the vertical distance covered, S=42.2 m, so the time of the fall is

S=\frac{1}{2}gt^2\\t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(42.2 m)}{9.8 m/s^2}}=2.93 s

And now we can consider the horizontal motion to find the horizontal distance covered by the stuffed chicken:

d=vt=(36.0 m/s)(2.93 s)=105.5 m

3) 49.4 m

Again, the motion of the ball is a projectile motion, with a horizontal motion and a vertical motion.

The range of a projectile launched from the ground can be found by using the formula:

d=\frac{v^2}{g} sin 2 \theta

where, in this case:

v = 22.0 m/s is the initial velocity

\theta=45^{\circ}

Substituting into the formula, we find

d=\frac{(22.0 m/s)^2}{9.8 m/s^2}(sin (2\cdot 45^{\circ}))=49.4 m

4) 9.6 m/s^2

The frictional force acting on the monkey is given by:

F_f = \mu mg=(0.16)(31.0 kg)(9.8 m/s^2)=48.6 N

where \mu is the coefficient of friction and m is the mass of the monkey.

We have two forces acting on the monkey: the push of F=345 N and the frictional force acting in the opposite direction. According to Newton's second law, the net force will be equal to the product between the monkey's mass and its acceleration, so we can find the acceleration:

F-F_f=ma\\a=\frac{F-F_f}{m}=\frac{345 N-48.6 N}{31.0 kg}=9.6 m/s^2

5) 462.3 N

The horizontal component of the pushing force is:

F_x = F cos \theta = (648 N)(cos 25^{\circ})=587.3 N

The frictional force, acting in the opposite direction, is

F_f = \mu mg=(0.17)(75.0 kg)(9.8 m/s^2)=125.0 N

where \mu is the coefficient of friction and m is the mass of the box.

The net force on the box is therefore given by the net force on the horizontal direction:

F_{net}=F_x -F_f=587.3 N -125.0 N=462.3 N

6) 89.5 N

First of all we need to calculate the total weight of the table and the items above it.

The weight of the table is:

W=mg=(25.0 kg)(9.8 m/s^2)=245 N

So the total weight of the table and the items is

W=245 N+63 N+12 N+44 N+24 N+9N+10N=407 N

The force needed to get the table moving must be at least equal to the frictional force, which is equal to the product between the coefficient of friction and the weight of the all stuff:

F=F_f = \mu W=(0.22)(407 N)=89.5 N

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2 years ago
3. Two bullets have masses of 0.003 kg and 0.006 kg, respectively. Both are fired with a speed of 40.0 m/s.
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Answer:

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B. When the mass is doubled the kinetic energy increases

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3 years ago
True or False
jasenka [17]
False . accelerating means to increase but moving at a constant speed means you stay the same .
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Answer:

Explanation:

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For rotational motion of hoop

Torque by tension

T x R ,      R is radius of hoop.

Angular acceleration be α,

Linear acceleration a = α R

So TR = I  α

= I  a / R

a = TR² / I

Putting this value in earlier relation

mg -T = m TR² / I

mg = T ( 1 + m R² / I )

T = mg / ( 1 + m R² / I )

mg / ( 1 + R² / k² )

Tension is less than mg or weight because denominator of the expression is more than 1.

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3 years ago
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