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Tpy6a [65]
4 years ago
14

Write a hypothesis about the effect of temperature and surface area on the rate of chemical reactions using this format: “If . .

. then . . . because. . . .” Be sure to answer the lesson question, “How do the factors of temperature and surface area affect the rate of chemical reactions?”
Physics
2 answers:
enot [183]4 years ago
7 0

Sample Response: If temperature and surface area increase, then the time it takes for sodium bicarbonate to completely dissolve will decrease, because increasing both factors increases the rate of a chemical reaction.

Marat540 [252]4 years ago
3 0

Explanation:

There are some factors that affect the rate of chemical reactions. These are as follows :

(1) Temperature  

(2) Surface area

(3) Catalyst effect

If the temperature increase, the rate of chemical reaction also increase because the particles start moving faster.

If the surface area increase, the rate if chemical reaction also increases because the chances of the collision become more. Hence, the reaction rate becomes fast.

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In both the U.S. House of Representatives and U.S. Senate, which of the selections below is elected by the party with the most m
Molodets [167]

I believe the answer is B

4 0
3 years ago
Are the plugs in your home connected in series or in parallel? and why?
yuradex [85]

Parallel. There are several reasons. Some are more technical, but the simplest reason is: If they were in series and somebody turned off the TV, all the lights in the house would go out, along with the air conditioner and the toaster.

In series, nothing can be running unless EVERYTHING is running. If one thing is unplugged or turned off, then EVERYTHING goes off.

If the house was wired in series, then every outlet would need something plugged into it AND turned on, otherwise you couldn't have a light in your bedroom. Pretty inconvenient !

8 0
4 years ago
Read 2 more answers
The current in a hair dryer measures 15 amps. The resistance of the hair dryer is 11 ohms. What is the voltage?
Cloud [144]

From Ohm's Law: V = I · R

Voltage = (current) · (resistance)

Voltage = (15 Amperes) · (11 ohms)

<em>Voltage = 165 volts</em>

5 0
3 years ago
A sled of mass 50 kg is pulled along a snow-covered, flat ground. The static friction coefficient is 0.3 and the kinetic frictio
Diano4ka-milaya [45]

Answer:

a) We kindly invite you to see below the Free Body Diagram of the forces acting on the sled.

b) The weight of the sled is 490.35 newtons.

c) A force of 147.105 newtons is needed to start the sled moving.

d) A force of 49.035 newtons is needed to keep the sled moving at a constant velocity.

Explanation:

a) We kindly invite you to see below the Free Body Diagram of the forces acting on the sled. All forces are listed:

F - External force exerted on the sled, measured in newtons.

f - Friction force, measured in newtons.

N - Normal force from the ground on the mass, measured in newtons.

W - Weight, measured in newtons.

b) The weight of the sled is determined by the following formula:

W = m\cdot g (1)

Where:

m - Mass, measured in kilograms.

g - Gravitational acceleration, measured in meters per square second.

If we know that m = 50\,kg and g = 9.807\,\frac{m}{s^{2}}, the weight of the sled is:

W = (50\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

W = 490.35\,N

The weight of the sled is 490.35 newtons.

c) The minimum force needed to start the sled moving on the horizontal ground is:

F_{min,s} = \mu_{s}\cdot W (2)

Where:

\mu_{s} - Static coefficient of friction, dimensionless.

W - Weight of the sled, measured in newtons.

If we know that \mu_{s} = 0.3 and W = 490.35\,N, then the force needed to start the sled moving is:

F_{min,s} = 0.3\cdot (490.35\,N)

F_{min,s} = 147.105\,N

A force of 147.105 newtons is needed to start the sled moving.

d) The minimum force needed to keep the sled moving at constant velocity is:

F_{min,k} = \mu_{k}\cdot W (3)

Where \mu_{k} is the kinetic coefficient of friction, dimensionless.

If we know that \mu_{k} = 0.1 and W = 490.35\,N, then the force needed to keep the sled moving at a constant velocity is:

F_{min,k} = 0.1\cdot (490.35\,N)

F_{min,k} = 49.035\,N

A force of 49.035 newtons is needed to keep the sled moving at a constant velocity.

8 0
3 years ago
An astronaut is in space with a baseball and a bowling ball. The astronaut pushes both objects in the same direction. If both ba
Crazy boy [7]

Answer:

As a mass greater than that of baseball, at the moment of the bowling wave the moment of the baseball ball is also greater

Explanation:

This problem is an application of momentum and momentum. When the astronaut pushed balls, he needed more force to move the ball of greater mass (bowling). The expression for soul is

      p = m v

Besibol Blade

      p1 = m1 v

Bowling ball

      p2 = m2 v

As a mass greater than that of baseball, at the moment of the bowling wave the moment of the baseball ball is also greater

      p2 >> p1

3 0
4 years ago
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