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Alekssandra [29.7K]
3 years ago
9

Solve by completing the square3x2 + x - 2 = 0​

Mathematics
1 answer:
DIA [1.3K]3 years ago
3 0

Answer:

x = 2/3 or x = -1

Step-by-step explanation by completing the square:

Solve for x:

3 x^2 + x - 2 = 0

Divide both sides by 3:

x^2 + x/3 - 2/3 = 0

Add 2/3 to both sides:

x^2 + x/3 = 2/3

Add 1/36 to both sides:

x^2 + x/3 + 1/36 = 25/36

Write the left hand side as a square:

(x + 1/6)^2 = 25/36

Take the square root of both sides:

x + 1/6 = 5/6 or x + 1/6 = -5/6

Subtract 1/6 from both sides:

x = 2/3 or x + 1/6 = -5/6

Subtract 1/6 from both sides:

Answer:  x = 2/3 or x = -1

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How many solutions are there to the functions? f(x)=3x+7
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Answer:

A. 0

Step-by-step explanation:

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3 years ago
Nora measured the angles of a triangle. Two of the angles measured 20° What was the measure of the third angle of Nora’s triangl
aivan3 [116]

Answer:

140°

Step-by-step explanation:

The sum of angle of a triangle is equal to 180°.

Two of the angles measured 20°.

We need to find the measure of the third angle of Nora’s triangle. let the third angle is x. So,

20+20+x = 180

40+x = 180

x = 180-40

x = 140°

So, the third angle of the triangle is 140°.

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3 years ago
What did sin theta/theta whisper worksheet answer key worksheet?
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First, we input 0, for theta in the function to obtain:
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This is an indeterminate form.

So, we apply L'Hopital's rule by differentiating the numerator and the denominator as follows:

\lim_{\theta \to 0} \frac{\sin\theta}{\theta}=\lim_{\theta \to 0} \frac{ \frac{d}{d\theta} (\sin\theta)}{\frac{d}{d\theta}\theta} \\  \\ =\lim_{\theta \to 0} \frac{\cos\theta}{1}=\cos0=1
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Lines are drawn on the gym floor for different sports for basketball playing area is marked so that there is an out of bounds. 2
choli [55]

Answer:

16 m  × 11 m

Step-by-step explanation:

The dimension of the gym is 20 m x 15 m. An outbound of 2m width is to be cut out from the gym to form the basketball court.

The original length of gym = 20 m and original width of gym = 15 m

2 m would be cut at both sides of the gym length for the outbound. Also 2 m would be cut at both sides of the gym width for the outbound. Therefore:

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Therefore the dimensions of the basketball court is:

16 m × 11 m

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3 years ago
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