21−=2(2−)=2cos(−1)+2 sin(−1)
−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2
Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.
complex-numbers
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edited Mar 6 '17 at 4:38
Richard Ambler
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asked Mar 6 '17 at 3:34
14wml
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1 Answer
1
No. It is not true that =cos()+sin(). Notice that
1=1≠cos()+sin(),
for example consider this at =0.
As a hint for figuring this out, notice that
+=ln(+)
then recall your rules for logarithms to get this to the form (+)ln().
Answer:
m(n) = 60000
Amount = 60000/n
Step-by-step explanation:
Given
Budget = 60000
Solving (a) Represent as a function mn
To do this simple substitute m(n) for Budget.
This gives;
m(n) = 60000
Solving (b) Amount each committee will receive.
Since the amount will be shared evenly.
Amount = m(n)/n
Substitute 60000 for m(n)
Amount = 60000/n
Answer:
-14
Step-by-step explanation:
The sum (addition) of the three numbers would be -14 because -12+-5 is -17. Then, -17+3 would be -14.
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