The exception is the element<span> hydrogen. ... solid at room temperature (with the exception of mercury); usually shiny; </span>high<span> melting point; good conductor of ... could be </span>dull<span> or shiny; conducts heat and electricity, but not as well as metals ... allotropes–</span>Phosphorus<span>, Selenium and Carbon (in the form of graphite.) ...</span>
The overall charge of the given compound of potassium and Arsenic is zero (0).
<h3>What is the charge of an atom?</h3>
An atom consists of a positively charged nucleus, surrounded by one or more negatively charged particles called electrons. When the number of protons exceed the number of electrons, the atom will positively charged and it will be negatively charged if the number of electrons exceed the number of protons.
For the given compound;
- KAs; As (Arsenic = -3) + K (potassium = +3)
- KAs overall charge = -3 + 3 = 0
Thus, the overall charge of the given compound of potassium and Arsenic is zero (0).
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The volume of the hydrogen gas would be 116.022 L
<h3>Density</h3>
The density of an object is a measure of how heavy the object is.
Mathematically, the density of an object is given by:
Density = mass/volume.
Thus, given 2 out of the 3 variables that make up the equation, the unknown variable can be calculated.
In this case, the mass and the density of hydrogen were given as 10.326 g and 0.089 g/L respectively.
Therefore, we need to find the volume by making it the subject of the formula from the equation above.
Volume = mass/density.
10.326/0.089 = 116.022 L
This means that the volume of the hydrogen gas is 116.022 L
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Answer:
C. polarity
Explanation:
Water is polar that is why it is a universal solvent.
Answer:
668.9K is the final temperature
Explanation:
The change in entropy, ΔS, of an ideal monoatomic gas is obtained using the equation:
ΔS = n*Cv*ln (T2/T1)
<em>Where ΔS is change in entropy = 200J/K</em>
<em>n are moles = 20.0mol</em>
Cv is 3/2R for an ideal monoatomic gas (3/2*8.314J/molK)
T2 is final Temperature and T1 initial temperature = 300K
Replacing:
ΔS = n*Cv*ln (T2/T1)
200J/K = 20.0mol*3/2 *8.314J/molK*ln (T2/300K)
0.80186 = ln (T2/300K)
2.23 = T2 / 300K
<h3>668.9K is the final temperature</h3>