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dolphi86 [110]
3 years ago
12

if a body is in motion at constant speed in a straight line, what, of any, forces could be acting on it

Chemistry
1 answer:
frez [133]3 years ago
4 0
Downward dog pose..........
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7 0
3 years ago
Which is an example of a physical change?
levacccp [35]

Answer:

salt dissolving

Explanation:

Hope this helps!

8 0
3 years ago
Read 2 more answers
I) What could Linda do to find out if there were salts dissolved in the
zhenek [66]

Answer:

she can use crystalization method.

Explanation:

She should boil that liquid on  flame and then cool it down on mederate temprature and check it out rather the crystals formed or not . if crystals are formed then there will be salts.

And if she want topredict the certain salt then she has to perform certain reactions.

6 0
3 years ago
If acid gets on your skin or clothes, wash at once with?
ICE Princess25 [194]
 water <span>t because washing with sulfuric acid wouldn't actually get any of the acid off of you, same with oil, just soothe it momentarily and stop burning of the skin by creating a barrier to the acid. If you wash with soap it will burn even more by activating some enzymes in the acid (depending on kind of acid) so washing with water is most practical because it gets all of the acid off immediately to stop more burns from occurring. I would recommend washing with water and then pouring oil onto the burn, to create a barrier. </span>
6 0
3 years ago
In preparation for a demonstration, your professor brings a 1.50−L bottle of sulfur dioxide into the lecture hall before class t
solmaris [256]

Answer:

4.81 moles

Explanation:

The total pressure of the gas = Pressure at which gauge reads zero + pressure read by it.

Pressure at which gauge reads zero = 14.7 psi

Pressure read by the gauge = 988 psi

Total pressure = 14.7 + 988 psi = 1002.7 psi

Also, P (psi) = P (atm) / 14.696

Pressure = 1002.7 / 14.696  = 68.2297 atm

Temperature = 25 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (25 + 273.15) K = 298.15 K  

Volume = 1.50 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

68.2297 atm × 1.5 L = n × 0.0821 L.atm/K.mol × 298.15 K  

⇒n = 4.81 moles

4 0
3 years ago
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