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Salsk061 [2.6K]
3 years ago
10

Please help need the answer tonight!!!!

Chemistry
1 answer:
Fynjy0 [20]3 years ago
4 0

Answer:

one its exothermic two i would say its five or forty

Explanation:

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Do all atoms only have one oxidation state​
MA_775_DIABLO [31]
I believe so! If not tell me So I can delete this
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What were the units of light energy emitted by blackbody radiation originally called?
Dafna11 [192]
The units of light energy emitted by blackbody radiation is originally called as quanta. Black body radiation is a type of radiation within a boy in thermodynamic equilibrium. This is a theoretical body. In 1900, Planck proposed that light and other electromagnetic waves were emitted in discrete packets of energy which were called "quanta". This was the original unit used.
5 0
4 years ago
I NEED HELPPP THIS DUE TODAY!!!! IT IS URGENT!!
Volgvan

Answer:

I don't really get what were supposed to be answering. if you give us a more clear question, it will be easier to answer! :)))

5 0
3 years ago
Carbon-14 is a radioactive isotope that decays according to first-order kinetics in a process that has a half-life of 5730 years
Sliva [168]

Answer : The time passed in years is 2.83\times 10^3\text{ years}

Explanation :

Half-life = 5730 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{5730\text{ years}}

k=1.21\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.21\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = ?

a = let initial amount of the reactant  = X g

a - x = amount left after decay process = 71\% \times (x)=\frac{71}{100}\times (X)=0.71Xg

Now put all the given values in above equation, we get

t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{X}{0.71X}

t=2831.00\text{ years}=2.83\times 10^3\text{ years}

Therefore, the time passed in years is 2.83\times 10^3\text{ years}

8 0
3 years ago
(Please explain the answer. Thank you!)
Dominik [7]

Sample cost = $15.796

<h3>Further explanation</h3>

Given

Mass = 2 g

Density = 0.718 g/ml

Cost =  $5.67 per mL

Required

Cost

Solution

The density : the ratio of mass and volume

Can be formulated :

Density (ρ) = m : V

The volume of the liquid :

V = m : ρ

V = 2 g : 0.718 g/ml

V = 2.786 ml

Sample cost :

= 2.786 ml x $5.67/ml

= $15.796

7 0
3 years ago
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