Remark
It is not a straight line distance from the park to the mall. None of the answers give you that result. And if you know what displacement is, none of the answers are really displacement either. The distance is sort of a "as the crow flies." distance. There's a stop off in the middle of town.
Method
You need to use the Pythagorean Formula twice -- once from the park to the city Center and once from the city center to the mall.
Distance from the Park to the city center.
a = 3 [distance east]
b = 4 [distance south]
c = ??
c^2 = 3^2 + 4^2 Take the square root of both sides.
c = sqrt(3^2 + 4^2)
c = sqrt(9 + 16) Add
c = sqrt(25)
c = 5
So the distance from the park to the city center is 5 miles
Distance from City center to the mall
a = 2 miles [distance east]
b = 2 miles [distance north]
c = ??
c^2 = a^2 + b^2 Substitute
c^2 = 2^2 + 2^2 Expand this.
c^2 = 4 + 4
c^2 = 8 Take the square root of both sides.
sqrt(c^2) = sqrt(8)
c = sqrt(8) This is the result
c = 2.8
Answer
Total distance = 5 + 2.8 = 7.8
Line Segment AB<span> ≅ Line Segment DB </span>
Answer:
1115322
Step-by-step explanation:
In 1906, San Francisco felt the impact of an earthquake with a magnitude of 7.8.
Claimed statement is he worst is yet to come, with an earthquake 142,990 times as intense as the 1906 earthquake ready to hit San Francisco.
We need to find the magnitude of their claimed earthquake.
It can be calculated by simply multiplying 142,990 by 7.8 as follows :
The magnitude of claimed earthquake is 1115322
.
Answer:
456 chairs
Step-by-step explanation:
If there are 6 round tables with 7 chairs each you would multiply 7, 6 times (7 x 6) = 42
If there are 23 rectangular tables with 18 chairs each you would multiply 18, 23 times. ( 18 x 23) = 414
Then you add up all the chairs, 456 chairs total.
If I'm wrong I'm so sorry
if I'm right Thank you (brainliest plz)
Answer: x = - 7
Step-by-step explanation:
