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3 years ago

What is the volume, in cubic units, of a pyramid of height 8 and a square base of length 15?

Mathematics

2 answers:

AURORKA [14]3 years ago

7 0

Answer:

900 cuboc unit

Step-by-step explanation:

Volume of pryamid= 1/3× area× height

= 1÷3×15^15×8

= 900cubic unit

Paraphin [41]3 years ago

6 0

For this case we have by definition, that the area of a square base pyramid is given by:

$V = \frac {L ^ 2 * h} {3}$

Where:

L: It's the side of the square base

h: It's the height of the pyramid

We have that $L = 15 \ units$ , then $L ^ 2 = 15 ^ 2 = 225 \ units ^ 2$

Substituting:

$V = \frac {225 * 8} {3}\\V = 600 \ units ^ 3$

Finally, the volume of the pyramid is $600 \ units ^ 3$

Answer:

$600 \ units ^ 3$

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A biology student wants to determine if using a fertilizer would help promote the growth of new babies in spider plants. The stu

sveticcg [70]

Answer:

Randomized block design

Step-by-step explanation:

From the question, we can see the following:

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Looking at all the statements above, it is clear that this is a randomized block design because a randomized block design is when the experimenter/researcher divides members/participants into subgroups called blocks in a manner that the variability within the blocks is less than the variability between the blocks. Thereafter, the participants within each block will now be randomly assigned to treatment conditions.

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3 years ago

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What is the peremeter of this tile 3in 3in 3in 3in I ready

Leokris [45]

Answer:

12 in.

Step-by-step explanation:

The perimeter is calculated by adding all up the sides of a shape. In this case, the shape is a square, considering that all the sides are the same measurements. 3+3+3+3 can be simplified to 3x4. This gives you 12 in. as the perimeter.

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3 years ago

The sum of 15 and the product of 5 and v

pogonyaev

The answer is 3 because 3×5=15

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3 years ago

The overhead reach distances of adult females are normally distributed with a mean of 197.5 cm197.5 cm and a standard deviation

fiasKO [112]

Answer:

a) 5.37% probability that an individual distance is greater than 210.9 cm

b) 75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c) Because the underlying distribution is normal. We only have to verify the sample size if the underlying population is not normal.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 197.5, \sigma = 8.3$

a. Find the probability that an individual distance is greater than 210.9 cm

This is 1 subtracted by the pvalue of Z when X = 210.9. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{210.9 - 197.5}{8.3}$

$Z = 1.61$

$Z = 1.61$ has a pvalue of 0.9463.

1 - 0.9463 = 0.0537

5.37% probability that an individual distance is greater than 210.9 cm.

b. Find the probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

Now $n = 15, s = \frac{8.3}{\sqrt{15}} = 2.14$

This probability is 1 subtracted by the pvalue of Z when X = 196. Then

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{196 - 197.5}{2.14}$

$Z = -0.7$

$Z = -0.7$ has a pvalue of 0.2420.

1 - 0.2420 = 0.7580

75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

The underlying distribution(overhead reach distances of adult females) is normal, which means that the sample size requirement(being at least 30) does not apply.

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3 years ago

( YOU’LL GET MARKED BRAINLIEST !! )

Mariulka [41]

Answer:

1/4

Step-by-step explanation:

The answer to this question is the amount of blue gummy bears over the total amount of gummy bears. This is 15/60 or 1/4.

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3 years ago

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