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3 years ago

A 10 Ω resistor is connected to a 120-V ac power supply. What is the peak current through the resistor?

Physics

1 answer:

11111nata11111 [884]3 years ago

8 0

Answer:

Peak current = 16.9 A

Explanation:

Given that

RMS voltage = 120 Volts

$V_{rms} = 120 V$

AC is connected across resistance

$R = 10 ohm$

now by ohm's law

$V = i R$

$120 = i (10)$

$i_{rms} = \frac{120}{10} = 12 A$

now peak value of current will be given as

$i_{peak} = \sqrt{2} i_{rms}$

$i_{peak} = \sqrt2 (12) = 16.9 A$

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