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Otrada [13]
2 years ago
12

Which of the following are true statements about electronegativity?Check all that apply.A. Electronegativity increases as you mo

ve to the right of the periodic table.B. Electronegativity is the ability of an atom to attract electrons.C. A very electronegative atom easily gives up electrons.D. Electronegativity increases with a decreased number of protons.
Physics
2 answers:
RUDIKE [14]2 years ago
7 0

Answer: A. Electronegativity increases as you move to the right of the periodic table.

B. Electronegativity is the ability of an atom to attract electrons.

D. Electronegativity increases with a decreased number of protons.

Explanation:-

Electronegativity is defined as the property of an element to attract a shared pair of electron towards itself.

The size of an atom decreases as we move across the period because the electrons get added to the same shell and the nuclear charge keeps on increasing. Thus the electrons get more tightly held by the nucleus.

As, the size of an element decreases, the valence electrons come near to the nucleus. So, the attraction between the nucleus and the shared pair of electrons increases.

Electronegativity increases when the protons increases as then the pull on electrons will be more.

stiks02 [169]2 years ago
4 0
I Know it is b i got my dad to help me with that test 

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Blababa [14]
Efficiency = (Wanted) energy out ÷ energy in × 100

Energy in = 400J
Wanted Energy out = 240J

Energy cannot be used up, only transferred, so the remaining energy is most likely to be transferred into unwanted energy (loss of energy) such as heat energy.

Efficiency = 240 ÷ 400 × 100
Efficiency = 0.6 × 100
Efficiency = 60%
8 0
3 years ago
3. A 142 g baseball is thrown at a speed of 42.9 m/s. What is the kinetic energy of the baseball at this moment?
krok68 [10]
Kinetic energy=1/2mv^2
=1/2(142*10^-3)(42.9)^2=130.6=131J
8 0
2 years ago
What speed would a proton need to achieve in order to circle Earth 1790 km above the magnetic equator, where the Earth's mag- ne
irinina [24]

Answer:

The velocity is 31.25 m/s and direction is toward west.

Explanation:

Given that,

Distance h= 1790 km = 1.790\times10^{6}\ m

Magnetic field B=4\times10^{-8}\ T

Mass of proton m=1.673\times10^{-21}\ Kg

Radius of earth R =6.38\times10^{6}\ m

Radius of orbit r=R+h

r=6.38\times10^{6}+1.790\times10^{6}

r=8170000\ m

We need to calculate the speed

Using formula of magnetic field

Bvq=\dfrac{mv^2}{r}

v=\dfrac{Bqr}{m}

Put the value into the formula

v=\dfrac{4\times10^{-8}\times1.6\times10^{-19}\times8170000}{1.673\times10^{-21}}

v=31.25\ m/s

Hence, The velocity is 31.25 m/s and direction is toward west.

6 0
3 years ago
The minimum stopping distance of a car moving at 20.5 mi/h is 11.6 m. Under the same conditions (so that the maximum braking for
pshichka [43]

Answer:

d = 69 .57 meter

Explanation:

First case

Speed of car ( v )  = 20.5 mi/h  = 9.164  M/S

distance ( d ) = 11.6 meter                                       ( m = mass of the car )

Work done = 0.5 m v²  = 0.5 * 9.164² * m J  = 41.99 m J

Force = ( workdone /distance ) = ( 41.99 m / 11.6 )   =  3.619 m N

Second case

v = 50.2 mi/h = 22.44135 m/s

d = ?

Work done = 0.5 * 22.44² * m J = 251.7768 * m J

Since the braking force remains the same .

3.619 m = ( 251.7768 m / d )

d = 69 .57 meter

7 0
3 years ago
The most common atom used in fission is ​
Eduardwww [97]

Answer:

Uranium

Explanation:

5 0
3 years ago
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