1.5 g of butane contains 6.21 x10^22 atoms of carbon.
Butane is an alkane that contains 4 moles of carbon atoms and 10 moles of hydrogen atom.
<h2>Further Explanation:</h2><h3>Moles, Atomic mass and Molar mass </h3>
- 1 mole of a pure substance contains a mass that is equal to the relative atomic mass or molecular mass of the substance.
- Therefore; molar mass is given as grams per mole of a substance
- Molar mass of any element is equal to the atomic mass of that element in the unit of grams.
- Hence;
- Molar mass = mass of a substance/ Number of moles
g/mol = g /mole
M = m/n; where M is the molar mass, m is the mass and n is the number of moles
- From this relationship we can therefore, calculate mass by multiplying the number of moles by molar mass of a substance.
That is; Mass = moles x molar mass
- To calculate number of moles;
We have; n = m/M
Number of moles = Mass of the substance/ Molar mass
- Molar mass is also equal to the mass of 6.02*10^23 particles of an element.
Therefore;
1 mole of particles = molar mass = 6.02 x 10^23 particles
<h3>
</h3><h3>In this case;</h3>
Step 1: moles of butane in 1.5 g of butane
Molar mass of butane is 58.1 g/mol
Therefore;
Moles of butane = mass in g/molar mass
= 1.50 g/58.1 g/mol
= 0.0258 moles
<h3>Step 2: Moles of Carbon in 1.5 g of butane </h3>
1 mole of butane contains 4 moles of carbon atoms.
Therefore; 0.0258 moles of butane will contain:
= 0.0258 moles x 4
= 0.1032 moles
Therefore, 1.5 g of butane contains 0.1032 moles of carbon atoms
<h3>Step 3: Number of atoms in 0.1032 moles of carbon atoms </h3>
Using Avogadro's constant;
1 mole of carbon atoms = 6.022 x 10^23 atoms
Therefore;
0.1032 moles of carbon atoms will contain;
= 0.1032 moles x 6.022 x 10^23 atoms
= 6.21 x 10^22 atoms
Keywords: Molar mass, moles, Avogadro's constant
<h3>Learn more about:</h3>
Level: High school
Subject: Chemistry
Topic: Moles
Sub-topic: Avogadros' law