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blondinia [14]
3 years ago
11

How many calories of heat were added to 381.9 g of water to raise its temperature from 25°C to 55°C?

Chemistry
1 answer:
fgiga [73]3 years ago
7 0

Answer:

About 7639.497 calories

Explanation:

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Solid potassium chlorate decomposes into solid potassium chloride and oxygen gas. If 2.00 g potassium chlorate decomposes in a c
abruzzese [7]

Answer : The final chamber pressure is 0.746 atm.

Explanation:

First we have to calculate the moles of KClO_3.

Molar mass of KClO_3 = 122.5 g/mole

\text{ Moles of }KClO_3=\frac{\text{ Mass of }KClO_3}{\text{ Molar mass of }KClO_3}=\frac{2.00g}{122.5g/mole}=0.0163moles

Now we have to calculate the moles of O_2.

The balanced chemical reaction will be:

2KClO_3\rightarrow 2KCl+3O_2

From the balanced reaction we conclude that,

As, 2 moles of KClO_3 react to give 3 moles of O_2

So, 0.0163 moles of KClO_3 react to give \frac{3}{2}\times 0.0163=0.0244 moles of O_2

Now we have to calculate the pressure of gas.

Using ideal gas equation:

PV=nRT

where,

P = pressure of gas = ?

V = volume of gas = 0.800 L

T = temperature of gas = 25.0^oC=273+25.0=298K

R = gas constant = 0.0821 L.atm/mole.K

n = number of moles of gas = 0.0244 mole

Now put all the given values in the ideal gas equation, we get:

P\times (0.800L)=0.0244mole\times (0.0821L.atm/mole.K)\times (298K)

P=0.746atm

Therefore, the final chamber pressure is 0.746 atm.

3 0
4 years ago
A small cube of iron and a large flat sheet of iron contain the same volume. Which one will completely rust first? Explain why.
allochka39001 [22]
Flat as more oxygen and water can react over it think of it like this would a cube rust faster than a sheet
6 0
3 years ago
What is the answer for O2 + C5H12O2 →?
ladessa [460]

Answer:

25.76

Explanation:

8 0
3 years ago
Brain break! Read the funny meme joke and answer "haha" to get free brain points, or post another joke! Funniest joke gets brain
Temka [501]

Answer:

hehehehe_________________________

8 0
3 years ago
Read 2 more answers
How many milliliters of 2.0 M NaCl solution would you need to make 250 ml of 0.15 M solution​
Stells [14]

Answer:

18.75 mL of NaCl solution is required.

Explanation:

Given data:

Molarity of solution one = 2.0 M

Volume of solution one = ?

Molarity of second solution = 0.15 M

Volume of second solution = 250 mL

Solution:

M₁V₁ = M₂V₂

V₁ = M₂V₂/M₁

V₁ = 0.15 M × 250 mL /  2.0 M

V₁ = 37.5 M.mL /  2.0 M

V₁ = 18.75 mL

5 0
4 years ago
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