Answer:
0.0202L
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
2HCl + Ba(OH)2 → BaCl2 + 2H2O
From the balanced equation above,
The mole ratio of the acid (nA) = 2
The mole ratio of the base (nB) = 1
Next, the data obtained from the question. This includes the following:
Molarity of acid (Ma) = 0.5M
Volume of acid (Va) =...?
Volume of base (Vb) = 0.050L
Molarity of base (Mb) = 0.101M
The volume of the acid, HCl needed for the reaction can be obtained as follow:
MaVa/MbVb = nA/nB
0.5 x Va / 0.101 x 0.05 = 2/1
Cross multiply to express in linear form
0.5 x Va = 0.101 x 0.05 x 2
Divide both side by 0.5
Va = (0.101 x 0.05 x 2)/0.5
Va = 0.0202L
Therefore, the volume of the acid, HCl needed for the reaction is 0.0202L