All categories

3 years ago

How many Liters of 0.50M HCl are needed to neutralize 0.050L of 0.101M Ba(OH)2?

Chemistry

2 answers:

Aleksandr-060686 [28]3 years ago

8 0

Answer:

$V_{HCl}=5.05x10^{-3}L$

Explanation:

Hello,

In this case, since hydrochloric acid and barium hydroxide are in a 2:1 molar ratio, for the neutralization, the following moles equality must be obeyed:

$2*n_{HCl}=n_{Ba(OH)_2}$

In such a way, in terms of molarities and volumes, we can compute the required volume of hydrochloric acid as shown below:

$2*M_{HCl}V_{HCl}=M_{Ba(OH)_2}V_{Ba(OH)_2}\\\\V_{HCl}=\frac{M_{Ba(OH)_2}V_{Ba(OH)_2}}{2M_{HCl}} =\frac{0.101M*0.050L}{2*0.50M} \\\\V_{HCl}=5.05x10^{-3}L$

Besr regards.

Nesterboy [21]3 years ago

7 0

Answer:

0.0202L

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2HCl + Ba(OH)2 → BaCl2 + 2H2O

From the balanced equation above,

The mole ratio of the acid (nA) = 2

The mole ratio of the base (nB) = 1

Next, the data obtained from the question. This includes the following:

Molarity of acid (Ma) = 0.5M

Volume of acid (Va) =...?

Volume of base (Vb) = 0.050L

Molarity of base (Mb) = 0.101M

The volume of the acid, HCl needed for the reaction can be obtained as follow:

MaVa/MbVb = nA/nB

0.5 x Va / 0.101 x 0.05 = 2/1

Cross multiply to express in linear form

0.5 x Va = 0.101 x 0.05 x 2

Divide both side by 0.5

Va = (0.101 x 0.05 x 2)/0.5

Va = 0.0202L

Therefore, the volume of the acid, HCl needed for the reaction is 0.0202L

You might be interested in

Write a mechanism (using curved-arrow notation) for the deprotonation of tannins in base. Use Ar-OH as a generic form of a tanni

Reika [66]

Answer:

After deprotonation of tannin, tannin (Ar-OH) is converted to $Ar-O^{-}Na^{+}$ salt which is soluble in water and $CO_{3}^{2-}$ is converted to $HCO_{3}^{-}Na^{+}$ which is also soluble in water

Explanation:

Sodium carbonate is a strong electrolyte which produces carbonate anion upon dissociation.
Carbonate ion is a strong conjugate base of weak acid $HCO_{3}^{-}$
After deprotonation of tannin, tannin (Ar-OH) is converted to $Ar-O^{-}Na^{+}$ salt which is soluble in water and $CO_{3}^{2-}$ is converted to $HCO_{3}^{-}Na^{+}$ which is also soluble in water
Balanced equation: $Ar-OH+Na_{2}CO_{3}\rightarrow Ar-O^{-}Na^{+}+Na^{+}HCO_{3}^{-}$
Mechanism has been shown below.

7 0

3 years ago

State one factor that effects the rate of change of the liquid colour

Debora [2.8K]

Answer:

Temperature is one of the major factors that affects the rate of change of the liquid colour, this is because ; like when if you freeze hot water the ice formed will be clear transparent, while on the other hand, if we freeze cold water it would be foggy inside the ice. This change occurs because of the temperature difference of the cold and hot water.

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

6 0

3 years ago

Which statement about the melting and boiling points of water and fluorine molecules is true?

raketka [301]

This is right its C i got a 5/5 :)

3 0

3 years ago

Read 2 more answers

which of the following elements are in this unbalanced chemical reaction: li(s) + H2O(l) lioh(aq)+h2(g)

Arada [10]

Answer:

Li and H

Explanation:

2Li(s)+2H2O(i)→2LiOH(aq)+H2(g) is full balanced

5 0

3 years ago

Read 2 more answers

What is the penetrating power of beta

zlopas [31]

The penetrating power of alpha rays, beta rays, and gamma rays varies greatly. Alpha particles can be blocked by a few pieces of paper. Beta particles pass through paper but are stopped by aluminum foil. Gamma rays are the most difficult to stop and require concrete, lead, or other heavy shielding to block them.

3 0

3 years ago