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seraphim [82]
3 years ago
12

What is the average acceleration during the time interval 0 seconds to 10 seconds?

Physics
1 answer:
zhuklara [117]3 years ago
3 0

Answer:

A. 0.5 m/s^2

Explanation:

The average acceleration is equal to the ratio between the change in velocity and the time elapsed:

a=\frac{\Delta v}{\Delta t}

The change in velocity between t=0 s and t=10 s is the change on the vertical axis:

\Delta v = 5 -0 = 5 m/s

Whule the time interval is

\Delta t = 10 s

So the average acceleration is

a=\frac{5 m/s}{10 s}=0.5 m/s^2

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a street light is mounted at the top of a 15 foot pole. A man 6 ft tall walks away from the pole wit a speed of 7 ft/s along a s
Mariulka [41]

Answer:

16.3 ft/s

Explanation:

Let d=distance

and

x = length of shadow.

Therfore,

x=(d + x)

 = 6/15

So,

    15x = 6x + 6d

     9x = 6d.

x = (2/3)d.

As we know that:

dx=dt

   = (2/3) (d/dt) 

Also,

Given:

d(d)=dt

     = 7 ft/s

Thus,

d(d + x)=dt

           = (7/3)d (d/dt)

Substitute, d= 7  

d(d + x) = 49/3 ft/s.

Hence,

d(d + x) = 16.3 ft/s.

4 0
3 years ago
Two marbles, one twice as heavy as the other, are dropped to the ground from the roof of a building. Just before hitting the gro
Andreyy89

Answer:

 B. twice as much kinetic energy

Explanation:

Lets take the mass of the first marble =2 m

the mass of the second marble = m

We know that velocity of particle does not depends on their mass that is the velocity of both mass will be same after dropping from the roof.

We know that kinetic energy of a mass is given as

KE=\dfrac{1}{2}Mv^2

Kinetic energy for heavier mass

KE=\dfrac{1}{2}\times 2m\times V^2

Kinetic energy for light mass

KE'=\dfrac{1}{2}\times m\times V^2

KE=2 KE '

Form above two equation we can say that ,the kinetic energy for the heavier mass is twice the lighter mass.

Therefore the answer will be B.

7 0
3 years ago
A string attached to an airborne kite was maintained at an angle of 40.0 with the ground. if 120m of string was reeled in to ret
AleksAgata [21]
The hypotenuse is measured at 120 meters of string, and you need to solve for the leg of the triangle that is horizontal. The degree is 40, so use trigonometry to figure it out. 
Cosin (40) is equal to around .766 
Adjacent/Hypotenuse 
x/120 = cos40 
Answer: 91.92533. 
If you use 3 significant figures it should be 91.9 meters.
5 0
3 years ago
6. A Cadillac Escalade has a mass of 2 569.6 kg, if it accelerates at 4.65m/S<br> force on the car?
SVETLANKA909090 [29]

Answer:

F= 2569.6 X 4.65 = 11,948.64

*Multiply the mass and the acceleration to find the force

Explanation:

5 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Fynjy0 [20]
D.
The reading between 7N and 8N would have to be 7.5N. Answers A and B are much to small and answer C is way to big.
8 0
3 years ago
Read 2 more answers
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