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Korvikt [17]
3 years ago
6

Electromagnetic force is present when electromagnetic fields

Physics
2 answers:
MAVERICK [17]3 years ago
6 0

Answer:

C- Interact with charged particles.

Explanation:

When a charged particle is placed in the field of the other charged particle then it will experience electromagnetic force on it.

aleksandr82 [10.1K]3 years ago
3 0

Answer: C; interact with charged particles.

Explanation: The elctromagnetic force is defined as:

F = q*E

Where q is the charge of a particle or charged object, and E is the electrical field, where the direction of the electric field defines the direction of the force.

Then, we need to have a charged particle in a outer eletrical field to have a electromagnetic force, which means that the correct answer is the option C; interact with charged particles.

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A child bounces in a harness suspended from a door frame by three elastic bands. If each elastic band stretches 0.300 m while su
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Answer:

The force constant for each elastic band is 77.93 N/m

Explanation:

Hooke's law of a spring or an elastic band gives the relation between elastic force (Fe) and stretching (x), the magnitude of that force is:

F_{e}= kx (1)

With k, the elastic force constant. The three elastic bands support the child’s weight (W) and maintain him at rest, so by Newton’s second law for one of the elastic bands:

\sum F=0 (2)

\frac{W}{3}-F_{e}=0\Rightarrow F_{e}=\frac{W}{3} (3)

Using (1) on (3):

kx=\frac{W}{3}\Rightarrow k=\frac{mg}{3x}(4)

k=\frac{7.15\,kg*9.81\,\frac{m}{s^{2}}}{3*0.300\,m}\simeq\mathbf{77.93\frac{N}{m}}

8 0
3 years ago
Explain how forces of attraction and repulsion exist within an atom
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7 0
3 years ago
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Of the cloud types described here, which one cannot be easily classified as low, middle, or high?
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a plane travels 2.5 km at an angle of 35 degrees to the ground and then changes Direction and travels 5.2 km and an angle of 22
Bess [88]

We can solve for the resultant x and y components by using the sine and cosine functions.

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resultant y = 2.5 sin 35 + 5.2 sin 22 = 3.38 km

 

The resultant displacement is calculated using hypotenuse equation:

displacement = sqrt (6.87^2 + 3.38^2)

displacement = 7.66 km

 

The resultant angle is:

θ = tan^-1 (3.38 / 6.87)

θ = 26.20°

 

Therefore the magnitude and direction is:

7.66 km, 26.20° to the ground

3 0
4 years ago
Determine the internal resistance of the capacitor.
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Answer:

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Explanation:

Hope this helps

7 0
2 years ago
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