Answer:
Data:-m=0.88kg ,g=9.8m/sec² ,P.E=96J ,h=?
Explanation:
solution ,P.E=mgh here we have to find h so h=P.E/mg ,h=96/0.88×9.8 ,h=96/8.624=11.131m and if you want to verify so just put the value of h in same formula, likewise :-P.E=mgh ,P.E=0.88×9.8×11.131=96J so we got the same value of P.E as it is given the question (verified).
A. Radio waves
Have the lowest frequencies
Answer:

Explanation:
= Length of wire = 65 m
= Initial current = 1.8 A
= Final current = 2.9 A
We know

and


so

The length of the wire remaining on the spool is
.
To develop this problem it is necessary to apply the equations concerning Bernoulli's law of conservation of flow.
From Bernoulli it is possible to express the change in pressure as

Where,
Velocity
Density
g = Gravitational acceleration
h = Height
From the given values the change of flow is given as

Therefore between the two states we have to



The flow rate will have changed to 54.77 % of its original value.