Answer:
4452.5 J.
Explanation:
The diver have both kinetic and potential energy.
Ek = 1/2mv² ................. Equation 1
Where Ek = Kinetic Energy of the diver, m = mass of the diver, v = velocity of the diver.
Given: m = 65 kg, v = 6.4 m/s.
Substitute into equation 1
Ek = 1/2(65)(6.4²)
Ek = 1331.2 J.
Also,
Ep = mgh ............................ Equation 2
Where Ep = Potential energy of the diver when its above the water, h = height of the diver above the water, g = acceleration due to gravity.
Given: m = 65 kg, h = 4.9 m, g = 9.8 m/s²
Substitute into equation 2.
Ep = 65(4.9)(9.8)
Ep = 3121.3 J.
Note: When she hits the water, the potential energy is converted to kinetic energy.
E = Ek+Ep
Where E = Kinetic energy of the diver when she hits the water.
E = 1331.2+3121.3
E = 4452.5 J.
Answer:
0.00903 rad
0.00926 rad
6.268\times 10^{-6}
Explanation:
s = Diameter of the object
r = Distance between the Earth and the object
Angle subtended is given by

For the Moon

The angle subtended by the Moon is 0.00903 rad
For the Sun

The angle subtended by the Sun is 0.00926 rad
Area ratio is given by

The area ratio is 
The charge present determines a force to be attractive or repulsive.
The charges acquired by two bodies determines the Force as Attractive Or Repulsive.
Electric Force applied due to Electrical charges is same in magnitude but opposite in direction. This corresponds this phenomenon equivalent to the Newton's Third Law.
Examples of the experiments and observations:
- On combing hair through a comb and then keeping it close to small pieces of paper shows attraction of paper pieces towards the comb.
This occurs due to the Electric charges present in the comb that induces charge in paper pieces leading to their attraction.
- In both Gravitational Force and Coulomb force, the force remains inversely proportional to the square of the distance following the Inverse Square Law being the Central Force system. This only differs by the fact that in Gravitational Force, masses are used and in Coulomb force, charges are used.
The more the distance between the charges, the less is the Electric Force.
The lesser the distance between the charges, the more is the Electric Force.
If both the objects are charged the same i.e. either positive or negative then the Force is Repulsive and if the charges are Oppositely charged then the force is attractive.
Hence, the charge present determines a force to be attractive or repulsive.
Learn more about Coulomb Force here, brainly.com/question/15451944
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The point of contact the path difference is zero but one of the interfering ray is reflected so the effective path difference becomes λ/2 thus the condition of minimum intensity is created in the center.
The ozone layer is one layer of the stratosphere, the second layer of the Earth’s atmosphere.