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o-na [289]
3 years ago
10

When all else remains the same, what effect would decreasing the focal length have on a convex lens?

Physics
2 answers:
murzikaleks [220]3 years ago
8 0

Answer: The correct answer is "it would make the lens stronger".

Explanation:

The power of the lens is defined as the reciprocal of the focal length. If the focal length of the smaller then the power of the lens will more and vice versa.

The power of the lens is measured in Diopter.

More the power of the lens, the stronger the lens would be. The power of the lens has an ability to bend the light. Greater the power of the lens, more the refraction of the light will be.

If the focal length of the convex lens is decreased then the convex lens would make the lens stronger.

Therefore, the correct option is "it would make the lens stronger".

aniked [119]3 years ago
4 0
<h3>Answer;</h3>

<u>It would make the lens stronger. </u>

<h3>Explanation;</h3>
  • The focal length is the distance between the optical center or the center of the lens to the focal point of a convex or concave lens.
  • The power of the convex lens is lens ability to undertake refraction or bend light. It is given as the reciprocal of focal length.
  • Power of the lens = 1/ f; therefore the smaller the focal length the higher the power and the larger the focal length the lower the power.
  • Thus; decreasing the focal length of a convex lens makes the lens stronger.

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Explanation:

Mass specific metabolic rate of a dolphin can be defined as the rate at which the dolphin consume energy per unit mass of body weight.

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3 years ago
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Answer:

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Please help!!!!
Dafna11 [192]

The intensity of the electric field is 30,000 N/C

Explanation:

The strength of the electric field produced by a single-point charge is given by the equation

E=k\frac{q}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q is the magnitude of the charge

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In this problem, we have:

q=3\cdot 10^{-9}C is the magnitude of the charge

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Substituting, we find:

E=(8.99\cdot 10^9)\frac{3\cdot 10^{-9}}{(0.03)^2}=30,000 N/C

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5 0
2 years ago
In a solution, the solvent is present in the larger amount. <br> A True <br> B False
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3 years ago
Two equal resistors are connected in series with a 1.50V battery. In order to keep the current at 0.030 A, the resistors much ea
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Answer: 25 Ohms

Explanation:

From this question, the following parameters are given:

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Current I = 0.03A

From Ohm's law;

V = IR

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Substitute V and I into the formula and make resultant R the subject of formula.

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R = 50 Ohms

From the question, it is given that Thr two equal resistors are connected in series.

R = R1 + R2

But R1 = R2

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R1 = 50/2

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Therefore, the resistors must each have a value of 25 Ohms

4 0
3 years ago
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