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o-na [289]
3 years ago
10

When all else remains the same, what effect would decreasing the focal length have on a convex lens?

Physics
2 answers:
murzikaleks [220]3 years ago
8 0

Answer: The correct answer is "it would make the lens stronger".

Explanation:

The power of the lens is defined as the reciprocal of the focal length. If the focal length of the smaller then the power of the lens will more and vice versa.

The power of the lens is measured in Diopter.

More the power of the lens, the stronger the lens would be. The power of the lens has an ability to bend the light. Greater the power of the lens, more the refraction of the light will be.

If the focal length of the convex lens is decreased then the convex lens would make the lens stronger.

Therefore, the correct option is "it would make the lens stronger".

aniked [119]3 years ago
4 0
<h3>Answer;</h3>

<u>It would make the lens stronger. </u>

<h3>Explanation;</h3>
  • The focal length is the distance between the optical center or the center of the lens to the focal point of a convex or concave lens.
  • The power of the convex lens is lens ability to undertake refraction or bend light. It is given as the reciprocal of focal length.
  • Power of the lens = 1/ f; therefore the smaller the focal length the higher the power and the larger the focal length the lower the power.
  • Thus; decreasing the focal length of a convex lens makes the lens stronger.

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Answer:

A

Explanation:

An antifreeze is a substance which when added to a liquid reduces the freezing point of the liquid. Hence the solution can only freeze at a lower temperature compared to the solvent. Examples of antifreeze includes salt and propylene glycol. Antifreeze are used in low temperature environments to prevent water from freezing quicky. Hence the answer is A.

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3 years ago
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The pupil of the human eye can vary in diameter from 2.00 mm in bright light to 8.00 mm in dim light. The eye has a focal length
Zarrin [17]

The indicated data are of clear understanding for the development of Airy's theory. In optics this phenomenon is described as an optical phenomenon in which The Light, due to its undulatory nature, tends to diffract when it passes through a circular opening.

The formula used for the radius of the Airy disk is given by,

y_r=1.22\frac{\lambda f}{d}

Where,

y_r = Range of the radius

\lambda = wavelength

f= focal length

Our values are given by,

State 1:

d=2.00mm = 2*10^{-3}m

f= 25mm = 25*10^{-3}m

\lambda = 750nm = 750*10^{-9}m

State 2:

d=8.00mm = 8*10^{-3}m

f= 25mm = 25*10^{-3}m

\lambda = 390nm = 390*10^{-9}

Replacing in the first equation we have:

y_{r1} = 1.22\frac{(750*10^{-9})(25*10^{-3})}{2*10^{-3}}

y_{r1}= 11.4\mu m

And also for,

y_{r2} =1.22\frac{(390*10^{-9})(25*10^{-3})}{8*10^{-3}}

y_{r2} = 1.49\mu m

Therefor, the airy disk radius ranges from 1.49\mu m to 11.4\mu m

7 0
3 years ago
A traffic light of weight 100 N is supported by two ropes that make 30-degree angle with the horizontal. What is the vertical co
alina1380 [7]

Answer:

T_{vertical} = 50 N

Explanation:

given,

traffic light weight = 100 N

angle at which the rope is supported = 30°

vertical component of force = ?

2 T sin \theta= W

2 T sin 30^0= 100

T = \dfrac{100}{2 sin 30^0}

T = 100\ N

T_{vertical} = T sin 30^0

T_{vertical} = 100\times \dfrac{1}{2}

T_{vertical} = 50 N

5 0
4 years ago
Determine the average normal stress developed in rod AB if the load has a mass of 55 kg . The diameter of rod AB is 8 mm.
Fudgin [204]

Answer:

The normal stress is 10.7[MPa]

Explanation:

The normal stress can be calculated with the following equation:

S_{norm} =\frac{F}{A} \\where:\\F= force [Newtons]\\A=area [m^2]\\S_{norm} = Normal stress [\frac{N}{m^{2} }] or [Pa]

The area of the rod can be calculated using the equation:

A=\frac{\pi }{4}*d^{2}  \\d=8[mm]=0.008[m]\\A=\frac{\pi }{4}*(0.008)^{2}  \\A=5.02*10^{-5} [m^{2} ]

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3 0
3 years ago
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Tju [1.3M]

Answer:

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