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castortr0y [4]
3 years ago
8

Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating a

bout a perpendicular axis at one end is ml2/3.
Physics
1 answer:
In-s [12.5K]3 years ago
4 0

Answer:

T = 1.108\,s

Explanation:

The period of a physical pendulum is:

T = \sqrt{\frac{I_{O}}{m\cdot g \cdot L} }

T=2\cdot \pi \sqrt{\frac{\frac{1}{3}\cdot m \cdot L^{2} }{m\cdot g\cdot L} }

T=2\cdot \pi \sqrt{\frac{L }{3\cdot g} }

The length of the leg is approximately the height of the person:

L = 0.915\,m

The period is:

T = 2\cdot \pi \sqrt{\frac{0.915\,m}{3\cdot (9.807\,\frac{m}{s^{2}} )} }

T = 1.108\,s

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Answer:

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Explanation:

From the question above, the following information was used to solve the problem.

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