First one:
(3x^2+5y^2)^3
Step 1: Use the binomial theorem to expand
(3x^2)+3(3x^2)^2(5y^2)+3(3x^2)(5y^2)2+(5y^2)^3
Step 2: Simplify each term
27(x^2)^3+3(3x^2)^2(5y^2)+3(3x^2)(5y^2)^2+(5y^2)^3
Step 3: Multiply the exponents
27x^6+27x^4(5y^2)+3(3x^2)(5y^2)^2+(5y^2)^3
27x^5+135x^4y^2+3(3x^2)(5y^2)^2+(5y^2)^3
Keep going to get the final answer:
27x^6+135x^4y^2+225x^2y^4+125y^6
2nd question: (2y^3-5x)^2
Do the same thing...step by step
Answer: 4y^6-20xy^3+25x^2
Answer:
y = -x+4; Use the slope formula (y2-y1/x2-x1) and work backwards using that formula.
4x + 6 < 3x - 5 is our given inequality
4x < 3x -11 by subtracting 6 on both sides of the inequality sign
x < -11 by subtracting 3x on both sides.
Thus, x < -11 -- choice D -- is the solution.
Answer:
97.95
Step-by-step explanation:
48.5438 x 16 1/7 = 783.6356286
783.6356286 ÷ 8 =97.95445357
round- 97.95
