Answer:
Claim 2
Step-by-step explanation:
The Inscribed Angle Theorem* tells you ...
... ∠RPQ = 1/2·∠ROQ
The multiplication property of equality tells you that multiplying both sides of this equation by 2 does not change the equality relationship.
... 2·∠RPQ = ∠ROQ
The symmetric property of equality says you can rearrange this to ...
... ∠ROQ = 2·∠RPQ . . . . the measure of ∠ROQ is twice the measure of ∠RPQ
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* You can prove the Inscribed Angle Theorem by drawing diameter POX and considering the relationship of angles XOQ and OPQ. The same consideration should be applied to angles XOR and OPR. In each case, you find the former is twice the latter, so the sum of angles XOR and XOQ will be twice the sum of angles OPR and OPQ. That is, angle ROQ is twice angle RPQ.
You can get to the required relationship by considering the sum of angles in a triangle and the sum of linear angles. As a shortcut, you can use the fact that an external angle is the sum of opposite internal angles of a triangle. Of course, triangles OPQ and OPR are both isosceles.
Step-by-step explanation:
-2x,7x and 2x,x3
look for the same variables or look if they both have a negative or a positive without a variable , example: -2.345 has the same terms as -5.99
Answer: -18 > -19
Step-by-step explanation:
Answer:
Maya, this is such a common question on here, so i'm very interested in what's difficult about this problem for you. Please comment about this. Below is the answer and how to find it.
Step-by-step explanation:
point P1 (5,35) in the form (x1,y1)
point P2(-6,-31) in the form (x2,y2)
slope = m
m = (y2-y1) / (x2-x1)
m = (-31-35) / (-6-5)
m = -66 / -11
they made it easy for you , huh
m = 6
use point / slope fomula, y-y1 = m(x-x1) and plug in one point, either would work, since i've already labeled it with point P1, let's use that point
y-35 = 6(x-5)
y-35 = 6x-30
y = 6x - 30 + 35
y = 6x + 5
Maya, this really is a very common question on here, I really am curious about what's tricky in the problem for you and many many others. please let me know in comments section, thanks MMM
Answer:
(40-y)^3
Step-by-step explanation:
Make the unknown y
(40-y)^3
