Answer:
The correct answer to the following question will be "Θ(n2)
". The further explanation is given below.
Explanation:
If we're to show all the objects that exist from either the first as well as the second vector, though not all of them, so we'll have to cycle around the first vector, so we'll have to match all the objects with the second one.
So,
This one takes:
=
And then the same manner compared again first with the second one, this takes.
=
Therefore the total complexity,
= Θ(n2)
Ctrl - and ctrl + i hope that is good for you
It would depend on the movie and the theater policy.....
Hope this helps have a good day
im not sure to be exact , but i think its england. i have done an assignment in the past and that was the awnser.....hope i help