Void test(char *s)
{
int i, d;
sscanf(s, "%i", &i);
printf("%s converts to %i using %%i\n", s, i);
sscanf(s, "%d", &d);
printf("%s converts to %d using %%d\n", s, d);
}
int main()
{
test("123");
test("0x123");
return 0;
}
outputs:
123 converts to 123 using %i
123 converts to 123 using %d
0x123 converts to 291 using %i
0x123 converts to 0 using %d
As you can see, %i is capable of parsing hexadecimal, whereas %d is not. For printf they're the same.
Answer:
hey! the answer to your question is -
binary is measured in base 2
The correct answer is B. Got it right on my review
B I think it is but I am not 100% sure on
Answer:
Following are the program to this question:
#include <iostream>//defining header file
using namespace std;
int recurs(int x, int n)//defining a method recurs that accepts two parameter
{
if(n==0)//defining if block that checks n value
{
return 1;//return value 1
}
else//defining else block
{
return x*recurs(x,n-1);//use return keyword that retun value
}
}
int main()//defining main method
{
cout<<recurs(5,3); //use print method to call recurs method
return 0;
}
Output:
125
Explanation:
In the above-given program, the integer method "recurs" is declared which accepts, two integer variables, which are "x, n", inside the method the if conditional statement is used.
- In the if block, it checks the value of n is equal to "0" if this condition is true, it will return a value, that is 1.
- Otherwise, it will go to the else block, in this block, it will use the recursive method to print its value.
