That's false. It's the other way around. One light year is a distance that's a little farther than 63,000 astronomical units.
The kinematics of the uniform motion allows us to find the final position vector
r = (-41.575 i + 42.253 j) m
Given parameters
- the starting position x = -17.5 m y = 23.1 m
- jump time t = 10.7 s
- The average velocities vₓ = -2.25 m / s and v_y = 1.79 m / s
to find
The uniform motion occurs when the velocity of the bodies is constant, in this case the relationship can be used for each axis
v =
x = x₀ + v t
Where vₓ it is the velocity, x the displacement, x₀ the initial position and t the time
Let's set a reference system with the horizontal x-axis. Regarding which we carry out the measurements
X axis
we look for the final position
x = x₀ + vₓ t
x = -17.5 -2.25 10.7
x = -41.575 m
Y Axis
we look for the final position
y = y₀ + v_y t
y = 23.1 + 1.79 10.7
y = 42.253 m
In conclusion, using the kinematics of uniform motion, find the final position vector
r = (-41.575 i + 42.253 j) m
learn more about uniform motion here:
brainly.com/question/17036013
Answer:
Frequency of sound wave = 198.83 hertz (Approx.)
Explanation:
Given:
Velocity of sound wave in air = 340 m/s
Wavelength = 1.71 meter
Find:
Frequency of sound wave
Computation:
Frequency = Velocity / Wavelength
Frequency of sound wave = Velocity of sound wave in air / Wavelength
Frequency of sound wave = 340 / 1.71
Frequency of sound wave = 198.8304
Frequency of sound wave = 198.83 hertz (Approx.)
Answer:
Since the resistors are in series, all of them carry the same current I.
if the potential drop across the 12 Ω is 4 V
I = 4 / 12 = 1/3 = .333 amp
a) 25 Ω * .333 amp = 8.33 V
b) 62 V * .333 amp = 20.7 V
Answer:
<h2>31km/h</h2>
Explanation:
Step one:
given data
speed of bus= 35km/h forward
speed of ball= 4km/h backwards
`Step two:
Required
the magnitude of the velocity of the ball relative to the ground is the net velocity
that is
=35-4
=31km/h
<em><u>The velocity of the ball relative to the ground is 31km/h</u></em>