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3 years ago

Two grocery carts have the same initial total momentum. The two carts collide, and now cart B has a greater final velocity.

Physics

2 answers:

Liula [17]3 years ago

9 0

Answer: The anser is C

Explanation:

It is the same if no external forces are added.

Angelina_Jolie [31]3 years ago

7 0

Answer:

Cart B has a smaller mass

Explanation:

I may be wrong but if mass is decreased then acceleration increases, and if velocity increases then acceleration increases so my logic is that if mass decreases then velocity increases.

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What happens if you move a magnet near a coil of wire?

monitta

A voltage appears between the ends of the wire. If the ends of the wire are connected, or if there is a conductor between them, then a current flows in the wire.

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3 years ago

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A good soccer player can kick the ball up to 25 m/sec. A soccer ball has a mass of 800 grams (0.8 kg). What force must a goalie

Oksana_A [137]

Answer:

200 N

Explanation:

Applying,

The force a golie must exert on the ball is,

F = ma...................... Equation 1

Where m = mass of the ball, a = acceleration of the ball.

But,

a = Δv/t............... Equation 2

Where Δv = change in velocity, t = time.

Substitute equation 2 into equation 1

F = m(Δv/t)............... Equation 3

From the question,

Given: m = 0.8 g, t = 0.1 s, Δv = 25 m/s

Substitute these values into equation 3

F = 0.8×25/0.1

F = 200 N

6 0

3 years ago

A man pushes an 80-N crate a distance of 5.0 m upward along a frictionless slope that makes an angle of 30 with the horizontal.

laiz [17]

Answer:

The work done by the man is 260 J.

(E) is correct option.

Explanation:

Given that,

Force = 80 N

Distance = 5.0 m

Angle = 30°

Acceleration = 1.5 m/s²

Let F be the man's force

We need to calculate the force

Using balance equation

$F-mg\sin\theta=ma$

$F-80\sin30=\dfrac{80}{9.8}\times1.5$

$F=\dfrac{80}{9.8}\times1.5+80\sin30$

$F=52\ N$

We need to calculate the work done by the man

Using formula of work done

$W=F\dotc d$

$W=52\times 5.0$

$W=260\ J$

Hence, The work done by the man is 260 J.

8 0

3 years ago

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What is the frequency of a clock waveform whose period is 750 microseconds?

stich3 [128]

The frequency f of a wave is defined as the inverse of the period T:
$f= \frac{1}{T}$
The clock in the problem has a waveform with period $T=750 ms=0.750 s$ . Therefore, its frequency is
$f= \frac{1}{0.750 s}=1.33 Hz$

6 0

4 years ago

Jenny was applying her makeup when she drove into the student parking lot last Friday morning . Unaware that Cheryl was stopped

Akimi4 [234]

Answer: F = 102141N

Explanation: Newton's 2nd Law states that a force can change the motion of a body. The relation is given by

F = m.a

whose units are:

[F] = N

[m] = kg

[a] = m/s²

Jenny's car, at the moment of the break, had acceleration:

$a=\frac{\Delta v}{\Delta t}$

$a=\frac{11}{0.14}$

a = 78.57 m/s²

Then, Force is

F = 1300*78.57

F = 102141 N

Jenny's car experienced a force of magnitude 102141N.

6 0

3 years ago