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3 years ago

12

If it takes 100 N to move a box 5 meters, what is the work done on the box?

1 answer:

inysia [295]3 years ago

7 0

Answer:

Explanation:

Work=force×distance

W=F×S

=100 N × 5 m

= 500 Nm

W = 500J

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An object in motion is usually seen moving in relation to an object that appears to

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At take off, a plane flies 100 km north before turning to fly 200 km east. How far is its destination from where the plane took

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A typical human lens has an index of refraction of 1.430 . The lens has a double convex shape, but its curvature can be varied b

rjkz [21]

Answer:

Maximum Power = 144.3 D

The associated focal length of the lens = $6.92*10^{-3} m$

Explanation:

According to the Lens maker's Formula:

$\frac{1}{f} = (n-1) (\frac{1}{R_1}-\frac{1}{R_2} )$

where;

$n_1$ = the refractive index of the medium

$R_1$ and $R_2$ = radius of curvature on each surface

For a convex lens, The radius of curvature in the front surface will be positive and that of the second surface will be negative . Therefore;

$\frac{1}{f} = (n-1) (\frac{1}{R_1}-\frac{1}{-R_2} ) \\ \\ \frac{1}{f} = (n-1) (\frac{1}{R_1}+\frac{1}{R_2} )$

At maximum power

$\frac{1}{f} = (1.430-1) (\frac{1}{6.50 \ mm}-\frac{1}{5.50 \ mm} )$

= $0.144 \ mm^{-1}$

This Implies

$f = 6.92 mm\\f = 6.92*10^{-3} \ m$

Therefore; the power is given by the formula:

$P_{max} = \frac{1}{f}$

$P_{max}= \frac{1}{6.92*10^{-3}}$

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4 years ago

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4. Ganymede ==>Jupiter
5. Triton ==> Neptune
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3 years ago

A sled is dragged along a horizontal path at a constant speed of 1.50 m/s by a rope that is inclined at an angle of 30.0° with r

Allisa [31]

Answer:2987.7 J

Explanation:

Given

sled weight is $W=470 N$

Tension in rope $T=230 N$

Time interval $t=10 s$

velocity of sled $v=1.5 m/s$

here speed is equal to velocity which is constant therefore acceleration is zero

thus $F_{net}=0$

Distance traveled in $t=10 s$

$x=v\times t=1.5\times 10=15 m$

considering surface to be friction less

thus $T\cos 30$ will do work on sled

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$W=T\cos 30\cdot x$

$W=230\cos 30\times 15$

$W=2987.78 J\approx 2.987 kJ$

4 0

4 years ago