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zepelin [54]
4 years ago
14

What happens to a liquid when it loses energy

Physics
1 answer:
NeTakaya4 years ago
8 0
It can solidify, it depends on the tempeture.
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at the extact same time, youj drop a piece of notebook paper and your science out the window. the science book hit first? why?
jeyben [28]
The piece of paper has less mass and will glide down the window, whereas the textbook will go straight to the ground. Since the textbook has more mass and less ways of it being able to 'glide' the textbook will hit the ground first.
8 0
3 years ago
The superheroine Xanaxa, who has a mass of 68.1 kg , is pursuing the 75.3 kg archvillain Lexlax. She leaps from the ground to th
Alexandra [31]

The concept required to solve this problem is associated with potential energy. Recall that potential energy is defined as the product between mass, gravity, and change in height. Mathematically it can be described as

U = mg\Delta h

Here,

\Delta h = Change in height

m = mass of super heroine

g = Acceleration due to gravity

The change in height will be,

\Delta h = h_f - h_i

The final position of the heroin is below the ground level,

h_f = -16.1m

The initial height will be the zero point of our system of reference,

\Delta h = -16.1m-0m

\Delta h = -16.1m

Replacing all this values we have,

U = mg\Delta h

U = (68.1kg)(9.8m/s^2)(-16.1m)

U = -10744.81J

Since the final position of the heroine is located below the ground, there will net loss of gravitational potential energy of 10744.81J

4 0
4 years ago
Estimate the moment of inertia of a bicycle wheel 66 cm in diameter. The rim and tire have a combined mass of 1.2 Kg
Fed [463]
<span>For a point mass the moment of inertia is just the mass times the square of perpendicular distance to the rotation axis, I = mr^2. That point mass relationship becomes the basis for all other moments of inertia since any object can be built up from a collection of point masses. So the I = (1.2 kg)(0.66m/2)^2 = 0.1307 kg m2</span>
3 0
3 years ago
A very delicate sample is placed 0.150 cm from the objective lens of a microscope. The focal length of the objective is 0.140 cm
iVinArrow [24]

Answer:

m = 14*26 = 364

Explanation:

overall magnification is given as m

m = m_{o}* m_{e}

mo magnification of objective lens

me magnification of EYE lens

where mo is given as

m_{o} = \frac{v_{o}}{-u _{0}}

and me as

m_{e} = 1+\frac{D}{f_{e}}

d is distant of distinct vision = 25.0 cm for normal eye

fe =  focal length of eye piece

focal length of objective lense is 0.140 cm

we know that

\frac{1}{v_{0}}-\frac{1}{u_{0}}=\frac{1}{f_{0}}

\frac{1}{v_{0}} = \frac{1}{u_{0}} + \frac{1}{f_{0}}

\frac{1}{v_{0}} = \frac{1}{0.150} + \frac{1}{0.14}

\frac{1}{v_{o}} = 2.1 cm

m_{o} = \frac{2.1}{0.150} = 14

m_{e} = 1+\frac{25}{1}

m_{e} =26

m = m_{o}* m_{e}

m = 14*26 = 364

4 0
3 years ago
If the number of particles of a gas is increased, the gas pressure will do what?
Inessa [10]
Gas pressure will also increase then.., if volume is kept constant
5 0
3 years ago
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