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rodikova [14]
3 years ago
7

A car is safely negotiating an unbanked circular turn at a speed of 25 m/s. The road is dry, and the maximum static frictional f

orce acts on the tires. Suddenly a long wet patch in the road decreases the maximum static frictional force to one third of its dry-road value. If the car is to continue safely around the curve, to what speed must the driver slow the car?
Physics
1 answer:
Brums [2.3K]3 years ago
8 0

Answer:

The velocity must be reduced to one third to stay on the road

Explanation:

The sideways force that friction must resist comes from the centrifugal acceleration due to the turn.

fc=mv2Rfc=mv2R

the frictional force is given by

ff=μmgff=μmg where μμ is the static friction coefficient

if the car is not to skid

fc≤fffc≤ff so    

mv2R≤μmgmv2R≤μmg

v≤μgR−−−−√v≤μgR

thus vv varies as the square root of μμ

so if μμ is reduced by 9, vv must be reduced by 9–√=39=3

and thus the speed must be reduced to<u> 26</u> m/s

                                                                    3

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The key to most of the achievements of mankind.?
Lapatulllka [165]

Answer:

Greatest Achievements of Mankind

-Declaration of Human Rights.

-United Nations.

-Leonardo Da Vinci's Mona Lisa.

-Michelangelo's Pieta.

-The Works of William Shakespeare.

-Technological achievements.

-The First Flight.

(please mark brainliest if correct/helped you <3)

8 0
2 years ago
Which quantities appear in the equation for the magnetic field component of an electromagnetic wave?
tankabanditka [31]

Answer:

The speed of light (c)

Explanation:

The equation that relates the magnetic field component of an electromagnetic wave the the electric field component of the wave is:

E=cB

where

E is the magnitude of the electric field component

B is the magnitude of the magnetic field component

c is the speed of light in a vacuum, whose value is

c=3.0 \cdot 10^8 m/s

Re-arranging the equation to solve for B, we find:

B=\frac{E}{c}

5 0
2 years ago
a piece of clay with mass m is traveling with an unknown velocity in the positive x-direction, when it collides and sticks to a
joja [24]

Answer:

13 m in the + x direction.

Explanation:

Givens

m1 = m

m2 = 3m

v1= ? = x

v2 = - 3 m/s

v3 = v4 = - 1 m/s

Equation

Let x be the speed of the lighter object before collision.

Momentum before collision = momentum after collision

Solution

mx   - 3m * 3m/s = (m1 + m2)*(-1)

m(x - 3*3m/s) = (m + 3m)(-1)

m(x - 9) = - 4m                                      Cancel the ms

x - 9 = 4                                                 Add 9 to both sides

x = 9 + 4

x = 13 m/s

7 0
3 years ago
A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area 0.320 m2. at
AlexFokin [52]
Remember, half of the energy in an EM wave is in the E field, the rest is in the B field. Thus, multiply E field energy by 2.
To calculate the energy of the wave you must then use the following equation: W = A*t*c*2*(1/2*E^2*Eo). Where, A = Area, t = time, c = speed of light (which is a constant), E = Electric field, E0 = vacuum permittivity (8.85*10^-12 Nm^2/C^2). Substituting W =(0.320)*(26)*(3*10^8)*(2)*((1/2)*(1.95*10^-2)^2*(8.854*10^-12)) = 8.40*10^-6 J
5 0
2 years ago
Part B
erik [133]

Answer:

Sound waves in liquids and gases involve alternating compression and rarefaction of material along a line defining the direction of propagation of the wave. These waves are known as longitudinal waves, and of course exist only in a medium that can be compressed and rarefied. In solids, sound energy also produces longitudinal waves, but it can also produce transverse waves, in which compression and rarefaction occurs perpendicular to the direction of propagation. These two waves propagate at different speeds, a phenomenon that is most noticeable in earthquakes. The first wave gives notice that the quake is coming, the second one does the damage. The time between the two tells you how far away the epicenter is. In water there is another kind of wave, called a gravity wave, the kind you see at the beach. All of these wave require a medium. There is no sound in a vacuum.

5 0
2 years ago
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