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disa [49]
3 years ago
11

What number is this in standard form? 5.6 times 10 to the negative ninth power (Note: Please explain this as best you can, and m

ake sure you show your steps. This is for a lot of points.)
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
7 0
Its called the internet
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The vertex of the function’s graph is given. Find c. y = x2 + 10x + c; (-5, -27)
castortr0y [4]
Actually I didn't see the (-5, -27), the answer would be -2.
5 0
3 years ago
In how many years will the interest of a sum of rs 3600 at the rate of 5.5% per year be rs 594?​
boyakko [2]

Answer:

In 3 years, the interest of a sum of rs 3600 at the rate of 5.5% per year be Rs 594.

Step-by-step explanation:

T = ?

R = 5.5%

P = Rs 3600

I = Rs 594

so

T = (I×100)/(P×R)

or, T = (594×100)/(3600×5.5)

or, T = 59400/19800

so, T = 3 yrs

7 0
2 years ago
A normal distribution has a mean of 14 and a standard deviation of 4. What percent of values are from 14 to 22?
Ivenika [448]

Answer:

80% of the values will occurs above 68.24.

Step-by-step explain

thinking this is right but im sorry if its wrong

3 0
3 years ago
out of some students appeared in an examination 80% passed in mathematics 75% passed in english and 5% failed in both subjects i
Advocard [28]

Answer:

5000 students appeared in the examination.

Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

Event A: Passed in Mathematics

Event B: Passed in English.

5% failed in both subjects

This means that 100 - 5 = 95% pass in at least one, which means that P(A \cup B) = 0.95

80% passed in mathematics 75% passed in english

This means that P(A) = 0.8, P(B) = 0.75

Proportion who passed in both:

P(A \cap B) = P(A) + P(B) - P(A \cup B)

Considering the values we have for this problem

P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.8 + 0.75 - 0.95 = 0.6

3000 of them were passed both subjects how many students appeared in the examination?

3000 is 60% of the total t. So

0.6t = 3000

t = \frac{3000}{0.6}

t = 5000

5000 students appeared in the examination.

4 0
2 years ago
Just answer what it asks in the picture PLEASE
Molodets [167]

m∠1 = 30° (by Vertical angle theorem)

m∠A = 80° (by Triangle sum theorem)

m∠D = 80° (by Triangle sum theorem)

The value of x is 7.5 and y is 9.

Solution:

∠ACB and ∠DCE are vertically opposite angles.

Vertical angle theorem:

<em>If two lines are intersecting, then vertically opposite angles are congruent.</em>

⇒ m∠DCE = m∠ACB

⇒ m∠1 = 30° (by Vertical angle theorem)

In triangle ACD,

Triangle sum property:

<em>Sum of the interior angles of the triangle = 180°</em>

⇒ m∠A + m∠C + m∠B = 180°

⇒ m∠A + 30° + 70° = 180°

⇒ m∠A + 100° = 180°

⇒ m∠A = 100° – 180°

⇒ m∠A = 80° (by Triangle sum theorem)

Similarly, m∠D = 80° (by Triangle sum theorem)

In ΔACD and ΔDCE,

All the angles are congruent, so ΔACD and ΔDCE are similar triangles.

<em>In similar triangle corresponding sides are in the same ratio.</em>

$\frac{9}{12}=\frac{x}{10}

Do cross multiplication.

90 = 12x

7.5 = x

Now, to find y:

$\frac{9}{12}=\frac{6}{y}

Do cross multiplication.

9y = 72

Divide by 9, we get

y = 8

Hence the value of x is 7.5 and y is 9.

7 0
3 years ago
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