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3 years ago

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A 1960 silver quarter is found to have a mass of 6.25 grams. On a given day, the value of silver is $17.32 per ounce. How much i

s this coin worth if the coin is 92% silver?

1 answer:

goldenfox [79]3 years ago

8 0

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Be sure to answer all parts. Nitric oxide (NO) reacts with molecular oxygen as follows: 2NO(g) + O2(g) → 2NO2(g) Initially NO an

Ivenika [448]

Answer:

The remain gases are $o_{2}_{(g)}$ and $NO_{2}_{(g)}$

Pressure of $O_{2}_{(g)}$ $1.09 atm O_{2}_{(g)}$

Pressure of $NO_{2}_{(g)}$ $1.09 atm NO_{2}_{(g)}$

Explanation:

We have the following reaction

$2NO_{(g)} +O_{2}_{(g)}\longrightarrow 2NO_{2}_{(g)}$

Now we calculate the limit reagents, to know which of the two gases is completely depleted and which one is in excess.

Excess gas will remain in the tank when the reagent limits have run out and the reaction ends.

To calculate the limit reagent, we must calculate the mols of each substance. We use the ideal gas equation

$PV= nRT$

We cleared the mols

$n=\frac{PV}{RT}$

PV=nrT

replace the data for each gas

Constant of ideal gases

$R= 0.082\frac{atm.l}{mol.K}$

Transform degrees celsius to kelvin

$25+273=298K$

$NO_{g}$

$n=\frac{0.500atm.3.90l}{298k.0.082\frac{atm.l}{k.mol} } \\ \\ n=0.080mol NO_{(g)} \\$

$O_{2}_{(g)$

$n=\frac{1atm.2.09l}{298k.0.082\frac{atm.l}{k.mol} } \\ \\ n=0.086mol O_{2}_{(g)} \\$

Find the limit reagent by stoichiometry

$2NO_{(g)} +O_{2}_{(g)}\longrightarrow 2NO_{2}_{(g)}$

$0.086mol O_{2}_(g).\frac{2mol NO_{(g)} }{1mol O_{2}_{(g)} } =0.17mol NO_{(g)}$

Using $O_{2}_{(g)}$ as the limit reagent produces more $NO_{(g)}$ than I have, so oxygen is my excess reagent and will remain when the reaction is over.

$NO_{(g)}$

$2NO_{(g)} +O_{2}_{(g)}\longrightarrow 2NO_{2}_{(g)}\\ \\ 0.080mol NO_{(g)}.\frac{1mol O_{2}_ {(g)} }{2mol NO_{(g)} } =0.04mol O_{2}_{(g)}$

Using $NO_{(g)}$ as the limit reagent produces less $O_{2}_{(g)}$ than I have, so $NO_{(g)}$ is my excess reagent and will remain when the reaction is over.

Calculate the moles that are formed of $NO_{2}_{(g)}$

$2NO_{(g)} +O_{2}_{(g)}\longrightarrow 2NO_{2}_{(g)}\\ \\ 0.080mol NO_{(g)}.\frac{2mol NO_{2}_ {(g)} }{2mol NO_{(g)} } =0.080mol NO_{2}_{(g)}$

We know that for all $NO_{(g)}$ to react, 0.04 mol $O_{2}_{(g)}$ is consumed.

we subtract the initial amount of $O_{2}_{(g)}$ less than necessary to complete the reaction. And that gives us the amount of mols that do not react.

$0.086-0.04= 0.046$

The remain gases are $O_{2}_{(g)}$ and $NO_{2}_{(g)}$

calculate the volume that gases occupy

$0.080 mol NO_{2}_{(g)} .\frac{22.4l NO_{2}_{(g)} }{1molNO_{2}_{(g)} }} =1.79 lNO_{2}_{(g)}$

$0.046 mol O_{2}_{(g)} .\frac{22.4 l O_{2}_{(g)} }{1molO_{2}_{(g)} }} =1.03 l O_{2}_{(g)}$

Calculate partial pressures with the ideal gas equation

$PV= nRT$

$P=\frac{nRT}{V}$

Pressure of $O_{2}_{(g)}$

$P=\frac{0.046mol.0.082\frac{atm.l}{K.mol} 298K}{1.03l}= 1.09 atmO_{2}_{(g)}$

Pressure of $NO_{2}_{(g)}$

$P=\frac{0.080mol.0.082\frac{atm.l}{K.mol} 298K}{1.79l}= 1.09 atmNO_{2}_{(g)}$

8 0

3 years ago

Read 2 more answers

Identify the neutralization reaction.

dusya [7]

The neutralization reaction among all the reactions would be the one between an acid and a base to produce salt and water.

<h3>What is a neutralization reaction?</h3>

It is a reaction involving an acid and a base to produce salt and water.

From the list of reactions, the only reaction that involves acid and a base with salt and water being the products is the first reaction.

Thus, the neutralization reaction is represented by the equation:

$2H_3PO_4 + 3Ba(OH)_2 --- > 6H_2O + Ba(PO_4)_2$

More on neutralization reactions can be found here: brainly.com/question/20038776

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2 years ago

True or false the three types of seismic waves are P eaves, S waves, and T waves

Vanyuwa [196]

False. The 3 types of seismic waves are P wave, S wave and Surface wave

3 0

3 years ago

Which of the following can be said in the crystallization of liquid salt.<br><br> A.

forsale [732]

Answer:

Correct option is D)

Explanation:

Crystallization is the process that is used to separate a pure solid in the form of its crystals from a solution.

Copper sulphate, salt, and potash alum can be purified by this method. In this process, the solution of the substance is heated and then cooled to form crystals.

8 0

2 years ago

Please help! Super easy, I just forgot!<br> Fill in the two blanks

Alborosie

Answer:

nucleuas

Explanation:

6 0

3 years ago