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nordsb [41]
3 years ago
6

What is a mass number​

Chemistry
1 answer:
wlad13 [49]3 years ago
7 0

Answer:

What is an mass number?

Mass number is an integer (whole number) equal to the sum of the number of protons and neutrons of an atomic nucleus. In other words, it is the sum of the number of nucleons in an atom. Mass number is often denoted using a capital letter A. Contrast this with the atomic number, which is simply the number of protons.

Explanation:

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How can a montain range cause a large dessert?
Simora [160]

Explanation:

An extensive mountain range can cause a large desert area.

Mountains are usually geologic features that have heights that are greater than 600m.

  • Due to towering heights of mountains, they have serious effect on the weather and climatic pattern in an area.
  • Air masses that are warm are usually moisture laden.
  • As they try to cross the steep slopy side of one mountain, their pressure reduces and they drop the vapor in them causing rainfall.
  • The cold wind moves to the other side.
  • This side is called the leeward side.
  • Cold air is dry and lacks moisture.
  • This can lead to the formation of a desert.

learn more:

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3 0
4 years ago
Practice Problem #2: How many atoms<br> of Ba are in 7.8 moles of Ba?
andriy [413]

7.8 \: mol =  \frac{6.02 \times  {10}^{23} atoms}{1 \: mol}  = 4.6956 \times  {10}^{24}  \: atoms

<em>round</em><em> </em><em>as</em><em> </em><em>you</em><em> </em><em>wish</em><em>.</em>

4 0
3 years ago
Help I’m so confused
ira [324]

Answer:

Me too.  What is this for? A Lab. You are missing some kind of key info bud.

Explanation:

4 0
3 years ago
Read 2 more answers
What mass of Al2(SO4)3 results from mixing 12.93 g of AlCl3 with 10.34 g of (NH4)2SO3 as shown with a 54.2% yield?
avanturin [10]

Mass of Al₂(SO₄)₃ : 4.822 g

<h3>Further explanation  </h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.  

Reaction

2AlCl₃ + 3(NH₄)₂SO₄⇒Al₂(SO₄)₃+ 6NH₄Cl

MW AlCl₃ :133,34 g/mol

MW (NH₄)₂SO₄ : 132,14 g/mol

MW Al₂(SO₄)₃ : 342,15 g/mol

mol  AlCl₃

\tt mol=\dfrac{12.93}{133.34}=0.097

mol (NH₄)₂SO₄

\tt mol=\dfrac{10.34}{132.14}=0.078

Limitng reactants (ratio mol : coefficient = the smaller)

AlCl₃ : (NH₄)₂SO₄ =

\tt \dfrac{0.097}{2}:\dfrac{0.078}{3}=0.0485:0.026

(NH₄)₂SO₄ ⇒ limiting reactants

So mol Al₂(SO₄)₃ from (NH₄)₂SO₄

\tt \dfrac{1}{3}\times 0.078=0.026

mass Al₂(SO₄)₃

\tt 0.026\times 342.15=8.896

with 54.2% yield, the mass of Al₂(SO₄)₃

\tt 0.542\times 8.896=4.822~g

7 0
3 years ago
Consider the following chemical reaction: CO (g) + 2H2(g) ↔ CH3OH(g) At equilibrium in a particular experiment, the concentratio
AlexFokin [52]

Answer:

The equilibrium concentration of CH₃OH is 0.28 M

Explanation:

For the reaction: CO (g) + 2H₂(g) ↔ CH₃OH(g)

The equilibrium constant (Keq) is given for the following expresion:

Keq= \frac{(CH3OH)}{(CO) x (H2)^{2}} =14.5

Where (CH3OH), (CO) and (H2) are the molar concentrations of each product or reactant.

We have:

(CH3OH)= ?

(CO)= 0.15 M

(H2)= 0.36 M

So, we only have to replace the concentrations in the equilibrium constant expression to obtain the missing concentration we need:

14.5= \frac{(CH_{3}OH) }{(0.15 M) x (0.36 M) ^{2} }

14.5 x (0.15 M) x (0.36)^{2} = (CH₃OH)

0.2818 M = (CH₃OH)

6 0
3 years ago
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