The answer is; A
By using a spring and determining the tension applied on the string by the car, it is possible to deduce the force. Determine the spring's initial tension as well as spring rate and working loads;
Rate = (Load – Initial Tension) ÷ Travel
k = (L – IT) ÷ T
Answer:
8.934 g
Step-by-step explanation:
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 192.12 44.01
H₃C₆H₅O₇ + 3NaHCO₃ ⟶ Na₃C₆H₅O₇ + 3H₂O + 3CO₂
m/g: 13.00
For ease of writing, let's write H₃C₆H₅O₇ as H₃Cit.
(a) Calculate the <em>moles of H₃Cit
</em>
n = 13.00 g × (1 mol H₃Cit /192.12 g H₃Cit)
n = 0.067 67 mol H₃Cit
(b) Calculate the <em>moles of CO₂
</em>
The molar ratio is (3 mol CO₂/1 mol H₃Cit)
n = 0.067 67 mol H₃Cit × (3 mol CO₂/1 mol H₃Cit)
n = 0.2030 mol CO₂
(c) Calculate the <em>mass of CO₂
</em>
m = 0.2030 mol CO₂ × (44.01 g CO₂/1 mol CO₂)
m = 8.934 g CO₂
???...........…..............
Answer:
The reactant that is reduced is
Explanation:
The complete equation is as below:
<em>Recall that oxidation involves the gain of electrons while reduction involves the loss of electrons.</em>
In the above reaction, loses electrons to coenzyme Q and becomes reduced to FAD, hence the oxidizing agent. Coenzyme Q gains electrons and becomes oxidized to , hence the reducing agent.
<u>In order words, </u><u> is reduced while coenzyme Q is oxidized.</u>
Answer:
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Explanation: