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kkurt [141]
3 years ago
12

Correct notation? im lost someone help?

Mathematics
1 answer:
joja [24]3 years ago
5 0

The correct notation for the \sqrt{-100} -84 is -84+10i.

Answer: Option B.

<u>Step-by-step explanation:</u>

A square root is the inverse function of exponential function.

Square root of positive numbers either result natural numbers or rational numbers.

But the square root of negative number is not possible. So that an imaginary number system was founded to represent the square root of negative number.

It is represented with i with the result of the solution of the square root.

Here the given problem is  \sqrt{-100} -84,

-84 will remain the same and let us convert \sqrt{-100}.

\sqrt{-100} can be written as \sqrt{100}×\sqrt{-1}.

\sqrt{100} = 10

\sqrt{-1} = i.

∴\sqrt{-100} =10i.

The correct notation for the \sqrt{-100} -84 is -84+10i

<u></u>

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Assume that X is a binomial random variable with n = 27 and p = 0.90. Calculate the following probabilities. (Do not round inter
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Answer:

a) P(X=26) = 27C26 (0.9)^{26} (1-0.9)^{27-26}= 0.1744

b) P(X=25) = 27C25 (0.9)^{25} (1-0.9)^{27-25}= 0.2520

c) P(X=25) = 27C25 (0.9)^{25} (1-0.9)^{27-25}= 0.2520

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P(X=27) = 27C27 (0.9)^{27} (1-0.9)^{27-27}= 0.0582

And addind the values we got:

P(X\geq 25)= P(X=25)+P(X=26)+P(X=27)=0.2520+0.1744+0.0582=0.4846

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem  

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=27, p=0.9)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Part a

We want this probability:

P(X=26)

And we can use the probability mass function and we got:

P(X=26) = 27C26 (0.9)^{26} (1-0.9)^{27-26}= 0.1744

Part b

We want this probability:

P(X=25)

And we can use the probability mass function and we got:

P(X=25) = 27C25 (0.9)^{25} (1-0.9)^{27-25}= 0.2520

Part c

We want this probability:

P(X\geq 25)= P(X=25)+P(X=26)+P(X=27)

And we can use the probability mass function and we got:

P(X=25) = 27C25 (0.9)^{25} (1-0.9)^{27-25}= 0.2520

P(X=26) = 27C26 (0.9)^{26} (1-0.9)^{27-26}= 0.1744

P(X=27) = 27C27 (0.9)^{27} (1-0.9)^{27-27}= 0.0582

And addind the values we got:

P(X\geq 25)= P(X=25)+P(X=26)+P(X=27)=0.2520+0.1744+0.0582=0.4846

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