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Arturiano [62]
3 years ago
12

In binocular rivalry, you see one image in the left eye and an incompatible image in the right eye. what do you perceive?

Physics
1 answer:
tankabanditka [31]3 years ago
8 0
What we perceive when we <span>see one image in the left eye and an incompatible image in the right eye using a binocular rivalry is that we usually see something halfway between one another. By definition, a binocular rivalry takes place when images gets alternated as presented in each eye.</span>
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Explanation:

It is known that wave intensity is the power to area ratio.

Mathematically,    I = \frac{P}{A}

As it is given that power is 28.0 W and area is 7 \times 10^{-5} m^{2}.

Therefore, sound intensity will be calculated as follows.

             I = \frac{P}{A}

               = \frac{28.0 W}{4 \times 3.14 \times 7 \times 10^{-5} m^{2}}

                = 0.318 \times 10^{5} W/m^{2}

or,             = 3.18 \times 10^{4} W/m^{2}

Thus, we can conclude that sound intensity at the position of the microphone is 3.18 \times 10^{4} W/m^{2}.

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Explanation:

(a)

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Using Snell's law as:

n_1\times {sin\theta_i}={n_2}\times{sin\theta_r}

Where,  

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Thus,

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The formula for the calculation of critical angle is:

{sin\theta_{critical}}=\frac {n_2}{n_1}

Where,  

{\theta_{critical}} is the critical angle

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No it cannot occur. It only occur when the light ray bends away from the normal which means that when it travels from denser to rarer medium.

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The atom is the most basic unit of matter 

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