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Arturiano [62]
3 years ago
12

In binocular rivalry, you see one image in the left eye and an incompatible image in the right eye. what do you perceive?

Physics
1 answer:
tankabanditka [31]3 years ago
8 0
What we perceive when we <span>see one image in the left eye and an incompatible image in the right eye using a binocular rivalry is that we usually see something halfway between one another. By definition, a binocular rivalry takes place when images gets alternated as presented in each eye.</span>
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An ice skater spins at 2.5 rev/s when his arms are extended. He draws his arms in and spins at 10.0 rev/s. By what factor does h
Rainbow [258]

Answer:

The moment of inertia decreased by a factor of 4

Explanation:

Given;

initial angular velocity of the ice skater, ω₁ = 2.5 rev/s

final angular velocity of the  ice skater, ω₂ = 10.0 rev/s

During this process we assume that angular momentum is conserved;

I₁ω₁ = I₂ω₂

Where;

I₁ is the initial moment of inertia

I₂ is the final moment of inertia

I_2 = \frac{I_1 \omega_1}{\omega_2} = \frac{I_1*2.5}{10} \\\\I_2 = 0.25I_1 = \frac{1}{4}I_1

Therefore, the moment of inertia decreased by a factor of 4

4 0
3 years ago
The supporting force exerted by a fluid on an object immersed in it is called ______.
aniked [119]

Answer: buoyant force

Explanation:

7 0
3 years ago
Read 2 more answers
If an object has a mass of 20 grams and a volume of 40 cm3, what is its density in g/cm3?
sattari [20]
Density = Mass/Volume 
So, given mass = 20 g and volume = 40 cm^3 
By substituting in above equation, Density = 20/40 = 0.5 g/cm^3
Hope it helps.

3 0
3 years ago
An alternative to CFL bulbs and incandescent bulbs are light-emitting diode (LED) bulbs. A 16-W LED bulb can replace a 100-W inc
Yanka [14]

Answer:

LED bulb = 0.145 A

Incandescent bulb = 0.909 A

CFL bulb = 0.218 A

Explanation:

Given:

Power rating of LED bulb (P₁) = 16 W

Power rating of incandescent bulb (P₂) = 100 W

Power rating of CFL bulb (P₃) = 24 W

Terminal voltage across the circuit (V) = 110 V

We know that, power is related to terminal voltage and current drawn as:

P=VI

Express this in terms of 'I'. This gives,

I=\frac{P}{V}

Now, calculate the current drawn in each bulb using their respective values.

For LED bulb, P_1=16\ W, V=110\ V

So, current drawn is given as:

I_1=\frac{16\ W}{110\ V}=0.145\ A

For incandescent bulb, P_2=100\ W, V=110\ V

So, current drawn is given as:

I_2=\frac{100\ W}{110\ V}=0.909\ A

For CFL bulb, P_3=24\ W, V=110\ V

So, current drawn is given as:

I_3=\frac{24\ W}{110\ V}=0.218\ A

Therefore, the currents drawn through LED bulb, incandescent bulb and CFL bulb are 0.145 A, 0.909 A and 0.218 A respectively.

5 0
3 years ago
Cells &amp; Cellular Processes
never [62]

Answer:

one or more cells

Explanation:

I need to have 20 characters to submit lol

7 0
3 years ago
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