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4 years ago

which measurment describes the amount of heat needed to raise the temperature of one gram of a material by one degree celsius?

Physics

1 answer:

ella [17]4 years ago

7 0

<u>Answer:</u>

Specific Heat

<u>Explanation:</u>

Specific heat is the measurement which describes the amount of heat needed to raise the temperature of one gram of a material by one degree Celsius.

It is the amount of heat required per unit mass to raise the temperature by one degree Celsius. The relationship between heat and the temperature change is usually expressed as shown below:

$Q=cm$ Δ $T$

where $Q$ = heat added,

$c$ = specific heat,

$m$ =mass; and

Δ $T$ = change in temperature

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Stella [2.4K]

The total is 21. If you use a calculator or count with your fingers it can help make the answer easier so in the end you will get 21 as your total.

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3 years ago

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If a personal pan pizza (6 inches in diameter) has 600 calories, how many calories would you consume if you were to eat a large

Neko [114]

Answer:

2400 calories

Explanation:

given,

diameter of pizza,d₁ = 6 inches

calories of the 6 inches pizza = 600 calories

diameter of large size of pizza, d₂ = 12 inches

calories of the 12 inches pizza = ?

Area of the 6 inches pizza

A₁ = π x 3² = 9 π

Area of the 12 inches pizza

A₂ = π x 6² = 36 π

Ratio of 12 inch pizza to 6 inches

= $\dfrac{36\pi}{9\pi}$

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calories of the pizza

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x = 2400 calories

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4 years ago

At time t=0 a 2150 kg rocket in outer space fires an engine that exerts an increasing force on it in the +x−direction. This forc

amm1812

Explanation:

Given that,

Mass of the rocket, m = 2150 kg

At time t=0 a rocket in outer space fires an engine that exerts an increasing force on it in the +x−direction. The force is given by equation :

$F=At^2$

Here F = 888.93 N when t = 1.25 s

$F=At^2\\\\A=\dfrac{F}{t^2}\\\\A=\dfrac{888.93}{(1.25)^2}\\\\A=568.91\ N/s^2$

The value of A is $568.91\ N/s^2$ .

(a) Let J is the impulse does the engine exert on the rocket during the 4.0 s interval starting 2.00 s after the engine is fired. It is given in terms of force as :

$J=\int\limits {F{\cdot} dt}$

Limits will be from 2 s to 2+ 4 = 6 s

It implies :

$J=\int\limits^6_2 {At^2{\cdot} dt}\\\\J=A\int\limits^6_2 {t^2{\cdot} dt}\\\\J=A\dfrac{t^3}{3}|_2^6\\\\J=568.91\times \dfrac{1}{3}\times (6^3-2^3)\\\\J=39444.42\ Ns$

(b) Impulse is also equal to the change in momentum as :

$J=m\Delta v\\\\\Delta v=\dfrac{J}{m}\\\\\Delta v=\dfrac{39444.42}{2150}\\\\\Delta v=18.34\ m/s$

Hence, this is the required solution.

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3 years ago

The speed of sound in air at room temperature is about s=343 m/s. calculate this speed in miles per hour (mph). (1 mi = 1609 m.)

igor_vitrenko [27]

Given:
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Also,
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iogann1982 [59]

I would say light. Hope this helps

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