All categories

3 years ago

Pablo preto lift a barbell. During which stage of the lift does Pablo do work on the barbell

Physics

2 answers:

Arlecino [84]3 years ago

6 0

While he is lifting the dumbell as the definition of work done = moving a mass through a distance = F x d

____ [38]3 years ago

3 0

this is the original question:

Pablo prepares to lift a barbell. During which stage of the lift does Pablo do work on the barbell?

when he holds the barbell up above his head

when he applies force to the barbell but has not moved it

when he lifts the barbell from the floor to his chest

when he lets go of the barbell and allows it fall to the ground

that is the answer-> when he lifts the barbell from the floor to his chest

hope this helps!

You might be interested in

A mars prototype carrying scientific instruments has a mass of 1060kg. a net force of 52000 n is applied to this roverat a test

Nitella [24]

F = 52000 N

m = 1060 kg

a= F/m = 52000 N/1060 kg = 49.0566 m/s^2

8 0

4 years ago

Two identical cars, one on the moon and one on the earth, have the same speed and are rounding banked turns that have the same r

Naily [24]

Answer:

The value of the centripetal forces are same.

Explanation:

Given:

The masses of the cars are same. The radii of the banked paths are same. The weight of an object on the moon is about one sixth of its weight on earth.

The expression for centripetal force is given by,

$F_{c} = \dfrac{mv^{2}}{r}$

where, $m$ is the mass of the object, $v$ is the velocity of the object and $r$ is the radius of the path.

The value of the centripetal force depends on the mass of the object, not on its weight.

As both on moon and earth the velocity of the cars and the radii of the paths are same, so the centripetal forces are the same.

3 0

3 years ago

The voltage entering a transformer’s primary winding is 120 volts. The primary winding is wrapped around the iron core 10 times.

loris [4]

<u>Answer</u>

48 Volts

<u>Explanation</u>
The question can be solve using the turn rule of a transformer that states;

Np/Ns = Vp/Vs
Where Np ⇒ number of turns in the primary coil.
Ns ⇒number of turns in the seconndary coil
Vp ⇒ primary voltage
Vs ⇒secondary voltage

Np/Ns = Vp/Vs

10/4 = 120/Vp

Vp = (120 × 4)/10

= 480/10
= 48 Volts

5 0

4 years ago

Read 2 more answers

Pleaseee someone help me TEST TOMORROW

Liono4ka [1.6K]

3.A

4.c

5.A
hope this helps

4 0

3 years ago

Read 2 more answers

The compressor on an air conditioner draws 66.1 a when it starts up. the start-up time is about 0.388 s. how much charge passes

Ierofanga [76]

The current intensity is defined as the amount of charge flowing through a certain point of a wire divided by the time interval:
$I= \frac{Q}{\Delta t}$
where Q is the charge and $\Delta t$ is the time. Re-arranging the formula, we have
$Q=I \Delta t$

for the compressor in our problem, the intensity of current is I=66.1 A, while the time is $\Delta t= 0.388 s$ , so the amount of charge that crosses a certain point of the circuit during this time is
$Q=I \Delta t=(66.1 A)(0.388 s)=25.65 C$

5 0

3 years ago