A person's temperature is 40

f an arrow is shot upward on the moon with velocity of 35 m/s, its height (in meters) after t seconds is given by h(t)=35t−0.83t

inysia [295]

Answer:

The velocity of the arrow after 3 seconds is 30.02 m/s.

Explanation:

It is given that,

An arrow is shot upward on the moon with velocity of 35 m/s, its height after t seconds is given by the equation:

$h(t)=35t-0.83t^2$

We know that the rate of change of displacement is equal to the velocity of an object.

$v(t)=\dfrac{dh(t)}{dt}\\\\v(t)=\dfrac{d(35t-0.83t^2)}{dt}\\\\v(t)=35-1.66t$

Velocity of the arrow after 3 seconds will be :

$v(t)=35-1.66t\\\\v(t)=35-1.66(3)\\\\v(t)=30.02\ m/s$

So, the velocity of the arrow after 3 seconds is 30.02 m/s. Hence, this is the required solution.

7 0

2 years ago

List three cases in which potential energy becomes

olga55 [171]

1 Electrical Potential Energy, separating two charged plates will store energy as the plates want to return to their original position.

<span>2 Spring or Elastic can be stretched to store energy as it wants to return to rest </span>

<span>3 Gravitational energy is stored by moving something (ball or pendulum are both examples of this) against a gravity gradient (lifting an object) that wants to fall back down. </span>

5 0

3 years ago

A crew on a spacecraft watches a movie that is two hours long. The spacecraft is moving at high speed through space. An Earth-ba

laiz [17]

Answer:

The duration of the movie is longer than 2 hrs.

Explanation:

Given:

The duration of the movie observed by the crew on the spacecraft is 2 hrs.

According to time-dilation formula:

$t = \dfrac{t_{0}}{\sqrt{1 - \dfrac{v^{2}}{c^{2}}}}$

Here, $t$ is the required time, $t_{0}$ is the original time, $v$ is the velocity of the spacecraft and $c$ is the velocity of light.

Since $v$ , so $t_{0} > t$ .

So the time required will be large.

4 0

2 years ago

Vega, the brightest star in the constellation lyra, has a parallax angle of approximately 0.13 arcseconds. approximately how far

Ivahew [28]

Vega, the brightest star in the constellation lyra, has a parallax angle of approximately 0.13 arcseconds, approximately Vega will be 25.076 Light year or 7.692 Parsec away from the sun

The parallax angle is the angle between the Earth at one time of year, and the Earth six months later, as measured from a nearby star.

Mathematically it can be understood as that the parallax angle is the angle which is taken from a point at one time on the earth and again after six months later from the same point on the earth. The parallax angle is the semi-angle of inclination between the two lines to sight.

Stellar parallax is the basis for the parsec, which is the distance from the Sun to an astronomical object that has a parallax angle of one arcsecond.

Distance (in parsec) = 1 / (parallax angle ( arcsec))

given

parallax angle = 0.13 arcseconds

Distance (in parsec) = 1/ 0.13 = 7.692 Parsec

if 1 Parsec = 3.26 Light year

So, 7.692 Parsec will be equal to = 3.26 * 7.692 = 25.076 Light year

≈ 25.076 Light year

To learn more about Stellar parallax here

brainly.com/question/4885471?referrer=searchResults

#SPJ4

5 0

1 year ago