The net force on q2 will be 1.35 N
A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.
Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.
We have to find the net force on q2
At first we will find Force due to q1
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²
F = 450 × 10⁻³
F₁ = 0.45 N (+)
Now we will find Force due to q2
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²
F = 1800 × 10⁻³
F₂ = 1.8 N (-)
So net force (F) will be
F = F₂ - F₁
F = 1.8 - 0.45
F = 1.35 N
Hence the net force on q2 will be 1.35 N
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The correct answer is B a magnetic field
Answer:
1. A
sound can't travel through vacuum only
Electrical energy is a particle that moves through a wire and transferred into homes, work, etc to make electricity work in objects.
1) Time to get the highest point of it pathway>
Vf = Vo - g*t
Vf = 0 (condition of maximum height)
Vo = 5.33 m/s
g = 9.81 m/s
=> t = Vo / g = 5.33 m/s / 9.81 m/s = 0.543 s
2) Time to return from the highest point = time to get to the highest point = 0.543 s
Total time = 0.543s + 0.543 s = 1.086 s ≈ 1.09 s
Answer: 1.09 s
