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wariber [46]
3 years ago
14

Define freezing....... Correct and detailed answers will be marked as Brainliest.

Chemistry
2 answers:
DIA [1.3K]3 years ago
7 0

Answer:

<u><em>Freezing:</em></u>

When liquid is converted to solid, the process is called freezing.

<u><em>Conditions for freezing:</em></u>

1) Temperature must be lowered.

2) The temperature should be below 0 degree centigrade.

<u><em>Example:</em></u>

The conversion of "liquid water" into "ice".

=> We can use a "freezer" to freeze things.

Nookie1986 [14]3 years ago
4 0
<h2>Freezing:</h2>

The transformation of liquid into solid when it reaches when it's temperature is below freezing point.

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If 5,800 j of energy are applied to a 15.2 kg piece of lead, by how much does the temp change if the specific heat of lead is 0.
scoray [572]

Answer:

The answer will be 2.98K

Explanation:

Using the formula:

Q = mc∆T

Q= 5,800 (heat in joules)

m= convert 15.2kg to g which is 15200g (mass in grams)

c= 0.128 J/g °c (Specific heat capacity)

∆T=  what we need to find (temperature change)

5800J = 15200g x 0.128 x ∆T

= 2.98K  

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3 years ago
Why is it necessary to obtain 25 to 50 hairs from this woman?
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To get the correct data

5 0
2 years ago
The pH of lemon juice is 2, and the pH of orange juice is 4. Which of these is more acidic, and by how much? What does this mean
katovenus [111]

Explanation:

The pH is a 1 to 14 scale that measures how acidic or basic is a solution, at lowest number the solution will be acid, in 7 the solution will be neutral, and in higher values will be basic. It is a  logarithmic scale, so with each number you move, the acidity or basicity will be increased by a factor of 10. So, lemon juice is more acidic than orange juice by a factor of 100.

5 0
2 years ago
2. A quantity of 1.922g of methanol (CH3OH) was burned in a constant-volume
Cerrena [4.2K]
Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
5 0
2 years ago
WORTH 100 POINTS
hjlf

Answer:

When 0.250 moles of a gas is placed in a container at 25 °C, it exerts a pressure of 700 mm Hg.

Explanation:

5 0
3 years ago
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