Answer:
Explanation:
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In this case, according to the given information, it turns out necessary for us remember that the first-order kinetics is given by:
Whereas the 27.5% complete means A/Ao=0.275, and thus, we solve for the rate constant as follows:
Then, we plug in the variables to obtain:
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Answer: A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen if it occupies 31.6 mL at
.
Explanation:
Given : Mass of oxygen = 0.023 g
Volume = 31.6 mL
Convert mL into L as follows.
Temperature =
As molar mass of is 32 g/mol. Hence, the number of moles of
are calculated as follows.
Using the ideal gas equation calculate the pressure exerted by given gas as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the value into above formula as follows.
Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen if it occupies 31.6 mL at
.